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liraira [26]
3 years ago
10

solve this problem as a quadratic equation. The difference between two positive numbers is 5. Their product is 104 find the numb

ers.
Mathematics
2 answers:
Karolina [17]3 years ago
8 0
Let's call the smaller number x:

y-x=5
xy=104

y-x=5 can be rewritten as y=x+5

Substituting this into the second equation gives:

x(x+5)=104
x^2+5x=104
x^2+5x-104=0

Then simply solve as a quadratic:

x^2+13x-8x-104=0
x(x+13) -8(x+13)=0
(x-8)(x+13) = 0

x=8,-13

the question said the numbers are positive, so x=8

if x=8,

y=x+5
y=13

So the two numbers are 8 and 13.
Salsk061 [2.6K]3 years ago
5 0
The best way to do this is to find the factors of 104. For this I got 1, 2, 4, 8, 13, 26, 52 and 104. From this, you are then able to look at the two that have a difference of five, which in this case, is 8 and 13. You should then double check that when these are multipled, they are equal to 104, which they are. I'm not 100% sure if this is the answer that you are looking for, but the two numbers are 8 and 13
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Answer:

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Step-by-step explanation:

So you want to get one side to equal zero so you can factor and find x. I recommend subtracting 14x and adding 45 to both sides so you don't have to deal with a negative quadratic.

X^2 - 14X +45 = 0

Now you can factor. Your looking for two factors that equal 45 and add to -14

All factors of 45:

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(X-5)(X-9)=0

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X-9=0 add 9 to both sides X=9

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The answer is

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