Let (x,y) be an arbitrary point on the circle.
Then d = √[x-3)2 + (y-0)2] = √[x2 - 6x + 9 + y2]
Since x2 + y2 = 1, y2 = 1-x2.
So, d = √[x2 - 6x + 9 + 1 - x2]
d = √(-6x+10)
Domain: x is the x-coordinate of a point on the circle centered at (0,0) with radius 1. So, -1≤x≤1.
But, for d to be defined, we need -6x+10 ≥ 0. So, x ≤ 5/3 (True for all x in [-1,1]).
Domain = [-1,1]
Range: -1 ≤ x ≤ 1 So, 6 ≥ -6x ≥ -6
16 ≥ -6x+10 ≥ 4
4 ≥ √(-6x+10) ≥ 2 That is, 2 ≤ d ≤4
Range: [2,4]
Step-by-step explanation:
The answer is D. 3/4
I hope this helped good luck!
Answer:
X>3
Step-by-step explanation:
X+9<4X
x-x+9<4x-x
9<3x
3<x
Answer:
09876543321
Step-by-step explanacdbhcybtfcbdshbcyhds\cdcd
Answer:

Step-by-step explanation:
Given function to us is ,
And, we need to find the inverse of the equation.
So , for that firstly replace x with y . The equation becomes
Now , next we need to solve for y .
Now , replace y for 

As per the options provided in Question we can that option (1) mathces with our answer when we just interchanged the variables.
<u>Hence</u><u> </u><u>option</u><u> </u><u>(</u><u>1</u><u>)</u><u> </u><u>is</u><u> </u><u>corre</u><u>ct</u><u>.</u>