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maria [59]
3 years ago
15

16. * MULTIPLE CHOICE Classify the fourth angle of a quadrilateral that

Mathematics
1 answer:
mash [69]3 years ago
8 0

Answer:

Obtuse

Step-by-step explanation:

The four angles in a quadrilateral must add up to 360 degrees. Since the three acute angles are each less than 90 degrees the last angle must be obtuse.

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P= (x,y) is an arbitrary point on the circle x^2+y^2=36
sesenic [268]

Let (x,y) be an arbitrary point on the circle.

Then d = √[x-3)2 + (y-0)2] = √[x2 - 6x + 9 + y2]

Since x2 + y2 = 1, y2 = 1-x2.

So, d = √[x2 - 6x + 9 + 1 - x2]

     d = √(-6x+10)

Domain:  x is the x-coordinate of a point on the circle centered at (0,0) with radius 1.  So, -1≤x≤1.

             But, for d to be defined, we need -6x+10 ≥ 0.  So, x ≤ 5/3  (True for all x in [-1,1]).

             Domain = [-1,1]

Range:    -1 ≤ x ≤ 1   So, 6 ≥ -6x ≥ -6

                                    16 ≥ -6x+10 ≥ 4

                                     4 ≥ √(-6x+10) ≥ 2   That is, 2 ≤ d ≤4

              Range:  [2,4]

Step-by-step explanation:

3 0
3 years ago
5. The points (2, 4) and (6,7) lie on a line. What is the slope of the line? A. 2 B. 1 C. 4/3 D. 3/4​
bearhunter [10]
The answer is D. 3/4

I hope this helped good luck!
3 0
3 years ago
What value of x makes this inequality true?<br> x+9 &lt; 4x
wariber [46]

Answer:

X>3

Step-by-step explanation:

X+9<4X

x-x+9<4x-x

9<3x

3<x

6 0
3 years ago
Help hurry pls. We are doing average rate of change and I need help
MrMuchimi

Answer:

09876543321

Step-by-step explanacdbhcybtfcbdshbcyhds\cdcd

7 0
3 years ago
What is the answer to this question?
krok68 [10]

Answer:

\boxed{\pink{\sf Option \ (1) \ is \ correct . }}

Step-by-step explanation:

Given function to us is ,

\implies y = 5x^2 + 10

And, we need to find the inverse of the equation.

So , for that firstly replace x with y . The equation becomes

\implies x = 5y^2 + 10

Now , next we need to solve for y .

\implies x = 5y^2 + 10 \\\\\implies 5y^2 = x - 10 \\\\ \implies y^2 = \dfrac{x-10}{5} \\\\\implies y = \sqrt{\dfrac{x-10}{5}}

Now , replace y for f^{-1}(x)

\underline{\boxed{\orange{\tt \implies f^{-1}(x) = \pm\sqrt{\dfrac{x-10}{5}}}}}

As per the options provided in Question we can that option (1) mathces with our answer when we just interchanged the variables.

<u>Hence</u><u> </u><u>option</u><u> </u><u>(</u><u>1</u><u>)</u><u> </u><u>is</u><u> </u><u>corre</u><u>ct</u><u>.</u>

4 0
3 years ago
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