The area of the shaded region is [(169π/4)-60]m².
- The length of the rectangle is 12 m.
- The breadth of the rectangle is 5 m.
- The area of the rectangle = length * breadth.
- The area of the rectangle = 12 * 5
- The area of the rectangle = 60m²
- Let h be the diagonal of the rectangle.
- Using the Pythagorean theorem,
- h² = 12² + 5²
- h² = 144 + 25
- h² = 169
- h = √169
- h = 13
- The diagonal of the rectangle is also the diameter of the circle.
- Let r be the radius of the circle.
- 2r = 13
- r = 13/2m
- The area of the circle is πr².
- The area of the circle = π(13/2)²
- The area of the circle = (169π/4)m²
- The area of the shaded region equals the area of the circle minus the area of the rectangle.
- The area of the shaded region = [(169π/4) - 60]m²
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Answer:
corresponding angle are all congruent
Answer:
<u>See answers below:</u>
- 1. AAS
- 2. ASA
- 3. SAS
- 4. HL
- 5. SSS
- 6. ΔABC ≅ ΔDFE
- 7. ΔTRS ≅ ΔTUV
- 8. ΔTRS ≅ ΔSUT
- 9. ΔCAB ≅ ΔFDE
The area of a square is:
A=s^2, solve this for s
s=√A
The "diagonal" is the hypotenuse of a right triangle with legs of length s.
By the Pythagorean Theorem:
d=√(s^2+s^2)
d=√(2s^2), and since we found that s=√A earlier:
d=√(2A), and since we are told that A=128m^2
d=√256
d=16m
