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Lelechka [254]
2 years ago
11

randall borrowed $850 from his parents to make some repairs on his car.He promised to repay the loan by giving his parents at le

ast $94 from his paycheck each week.
Mathematics
2 answers:
Lana71 [14]2 years ago
7 0
He needs about 10 weeks to completely pay off the debt but with nine weeks he pays off 846, so he needs the 10th week to pay off the last 4 bucks
sammy [17]2 years ago
4 0

Then, he would take = $850/94 = 9.04

atleast 9.04 weeks for repaying that.......

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Zina [86]
So it seems as if the first problem is asking this:

2 \frac{1}{6} - \frac{11}{15}x. 

If x=0.15, then 11/15*(0.15) is 0.11 or 11/100. 

The second problem is asking:

\frac{x}{4} + \frac{1}{2} = \frac{x}{3} + \frac{1}{6}

To solve algebraically, you want to get rid of the denominators under the x's. To do so, you want to multiply by the Least Common Multiple (LCM) of the denominators. For 3 and 4, the LCM is 12. Multiply everything by 12 to get:

3x+6=4x+2

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3 years ago
Read 2 more answers
I am stuck with question 9.b on Algebra
MrMuchimi
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3 years ago
Write the equation in siope-intercept form for the line that passes through the given pointand is perpendicular to the given equ
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For a line in the form:

\begin{gathered} ax+by=c \\ The\text{ slope m is:} \\ m=-\frac{a}{b} \end{gathered}

In this case, for the line 2x + 10y = 20 with a=2 and b=10 the slope is:

\begin{gathered} m_1=-\frac{a}{b}=-\frac{2}{10} \\ m_1=-\frac{1}{5} \end{gathered}

Now, two lines are perpendiculars if the slopes satisfy the following equation:

m_2=-\frac{1}{m_1}

So, for the line we want the slope is:

\begin{gathered} m_1=-\frac{1}{5} \\ m_2=-\frac{1}{m_1}=-\frac{1}{(-\frac{1}{5})}=5 \end{gathered}

Finally, the line pass througth the point (2, 3) with slope m=5, so the equation is:

\begin{gathered} P_1=(2,3),m=5 \\ y=mx+b \\ \text{The P1 must satisfy the equation:} \\ 3=5\cdot2+b \\ b=3-10 \\ b=-7 \end{gathered}

The equation of the line is y = 5x - 7

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1 year ago
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