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3 years ago

Please answer this correctly

Mathematics

2 answers:

mixas84 [53]3 years ago

7 0

Answer:

Step-by-step explanation:

This is the answer because one number that is select is one. A number greater than 2 is 3. SO it is 2/3.

rewona [7]3 years ago

3 0

Answer:

2/3

Step-by-step explanation:

There are 2 numbers out of 3 that fit the rule, 1 and 3. There is a 2/3 chance picking one of them.

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Indi bought a shirt for $30. He paid 7% sales tax. How much sales tax did Indie pay?

ivann1987 [24]

He paid $ 32.10

because

07 * 30 = 2.10

2.10 + 30 = $ 32.10

7 0

3 years ago

Can anybody figure this question out cause I can't figure it out.

Kazeer [188]

Answer:

there is no change because it is a circle

4 0

3 years ago

Ms.Henderson is using triangles in her graphic design project.The triangles are isosceles.One had a base of 4 inches and legs of

tester [92]

If the two triangles are similar you can use a proportion to solve for the length of the legs.
$\frac{2}{4}$ = $\frac{x}{9}$
Now, you would cross multiply to get
4x=18
Now, you simplify that using the division property of equality.
You end up with
x=4.5
Therefore, the legs of the triangle with a base of 9 inches will each be 4.5 units long.

4 0

3 years ago

The equation 7^2=a^2 shows the relationship between a planet’s orbital period, T, and the planet’s mean distance from the sun, A

jeyben [28]

Answer:

The period of Y increases by a factor of $k^ {3/2}$ with respect to the period of X

Step-by-step explanation:

The equation $T ^ 2 = a ^ 3$ shows the relationship between the orbital period of a planet, T, and the average distance from the planet to the sun, A, in astronomical units, AU. If planet Y is k times the average distance from the sun as planet X, at what factor does the orbital period increase?

For the planet Y:

$T_y ^ 2 = a_y ^ 3$

For planet X:

$T_x ^ 2 = a_x ^ 3$

To know the factor of aumeto we compared $T_x$ with $T_y$

We know that the distance "a" from planet Y is k times larger than the distance from planet X to the sun. So:

$a_y ^ 3 = (a_xk) ^ 3$

$\frac{T_y ^ 2}{T_x ^ 2}=\frac{a_y ^ 3}{a_x^ 3}\\\\\frac{T_y ^ 2}{T_x ^ 2}=\frac{(a_xk)^3}{a_x ^ 3}\\\\\frac{T_y^ 2}{T_x^ 2}=\frac{k ^ {3}a_{x}^ 3}{a_{x}^ 3}\\\\\frac{T_{y}^ 2}{T_{x}^ 2}=k ^ 3\\\\T_{y}^ 2 = T_{x}^{2}k^{3}\\\\T_{y} =k^{\frac{3}{2}}T_x$

Then, the period of Y increases by a factor of $k^ {3/2}$ with respect to the period of X

4 0

3 years ago

Find the value of the variable in the polygon.

galben [10]

Answer:

103

Step-by-step explanation:

This shape is pentagon.

Note : -

Sum of interior angles of a pentagon is 540.

115 + 105 + 117 + 100 + x = 540

437 + x = 540

x = 540 - 437

x = 103

7 0

2 years ago