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2 years ago

The height of a fish tank is 1.1 feet, and the area of the tank's base is

Mathematics

1 answer:

SashulF [63]2 years ago

8 0

Answer:

Step-by-step explanation:

volume = 1.1 ft × 14 ft² = (1.1×14) ft³ = 15.4 ft³

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Please show work thank you math experts

AlekseyPX

Answer:

1. 35 - 176 = -141

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3. 11.38 × 5.46 = 62.1348

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1 year ago

I have a LOT of trouble in math. Can you guys help me with these questions? thanks

ASHA 777 [7]

1. 5/8 + 1/8 = 6/8 --> 3/4

3. - 1/4+ 3/4:

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5. 5/9 + 5/9 = 10/9 --> 1 whole 1/9

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And I simplified them too :P

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2 years ago

Lavel the vertex and axis of symmetry

Lostsunrise [7]

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2 years ago

Find the minimum and maximum of f(x, y, z) = y + 4z subject to two constraints, 2x + z = 4 and x2 + y2 = 1. g

yuradex [85]

$L(x,y,z,\lambda_1,\lambda_2)=y+4z+\lambda_1(2x+z-4)+\lambda_2(x^2+y^2-1)$

$L_x=2\lambda_1+2\lambda_2 x=0\implies\lambda_1+\lambda_2x=0$
$L_y=1+2\lambda_2y=0$
$L_z=4+\lambda_1=0\implies\lambda_1=-4$
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$x^2+y^2=1\implies (-8y)^2+y^2=65y^2=1\implies y=\pm\dfrac1{\sqrt{65}}$
$y=\pm\dfrac1{\sqrt{65}}\implies x=\mp\dfrac8{\sqrt{65}}$
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We have two critical points to consider: $\left(-\dfrac8{\sqrt{65}},\dfrac1{\sqrt{65}},4+\dfrac{16}{\sqrt{65}}\right)$ and $\left(\dfrac8{\sqrt{65}},-\dfrac1{\sqrt{65}},4-\dfrac{16}{\sqrt{65}}\right)$ .

At these points, we respectively have a maximum of $16+\sqrt{65}$ and a minimum of $16-\sqrt{65}$ .

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2 years ago

I need help in my math homework

vovikov84 [41]

The answer for 13. C and 14. B.

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2 years ago

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