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Darina [25.2K]
3 years ago
6

Can anybody figure this question out cause I can't figure it out​.

Mathematics
1 answer:
Kazeer [188]3 years ago
4 0

Answer:

there is no change because it is a circle

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A tube is being stretched while maintaining its cylindrical shape. The height is increasing at the rate of 2 millimeters per sec
hoa [83]

Answer:

V = πr²h

S=2πrh

h= 2/3 millimeters

new height= 8/3 millimeters

S= 8π  millimeters square

New surface area = 32π  millimeters square

Step-by-step explanation:

The volume of the cylinder is given by V = πr²h   where r is the radius and h is the height.

The surface area of the cylinder is given by  S= 2πrh + 2πr²

Where πr² gives the area of the base and 2πr² gives the area of the top and bottom surfaces. The surface area S of a cylinder, not including the top and bottom of the cylinder, is therefore S=2πrh.

V = πr²h

96π= π (6*6) (h+2)

96 = 36 (h+2)

96/36= h+2

h= 96/36-2

h= 96-72/36

h= 24/36

h= 4/6

h= 2/3 millimeters

New height

h + 2= 2/3 + 2

= 2+6/3= 8/3 millimeters

Now S =2πrh

S = 2π(6) (2/3)

S= 8π  millimeters square

New Surface area

S = 2π(6) (8/3)

S= 32π  millimeters square

6 0
3 years ago
Complete this statement:
klasskru [66]

Answer:

45x^3a+27xa^2= 9xa(5x^2+3a)

Step-by-step explanation:

Given:

45x^3a+27xa^2= 9xa

We need to complete this Statement.

By Solving the above equation we get;

We will take some common factor out so we will get;

45x^3a+27xa^2= 9xa(5x^2+3a)

Hence the Complete statement is 45x^3a+27xa^2= 9xa(5x^2+3a)

5 0
3 years ago
What is the simplify ratio 40:28
Simora [160]
40:28  = 10:7 simplified 
3 0
3 years ago
Evaluate 5x-2w+t <br><br> Help needed!!
likoan [24]

the answer is the same

5 0
3 years ago
What is the value of x?
Alexus [3.1K]

Answer:

x = 22.5

Step-by-step explanation:

\frac{BH}{DH}  =  \frac{HM}{HT}  \\  \frac{6}{15 + 6}  =  \frac{9}{9 + x}  \\  \frac{6}{21}  =  \frac{9}{9 + x}  \\ 6(9 + x) = 9 \times 21 \\ 54 + 6x = 189 \\ 6x = 189 - 54 \\  6x = 135 \\ x =  \frac{135}{6}  \\ x = 22.5

5 0
3 years ago
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