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vagabundo [1.1K]
3 years ago
5

(I NEED THIS ANSWERED QUICKLY! I WILL GIVE BRAINLIEST TO FIRST CORRECT ANSWER!)

Mathematics
1 answer:
almond37 [142]3 years ago
4 0

Answer:

Option A \sqrt{187.95}\ Km

Step-by-step explanation:

we know that

Applying the Pythagorean Theorem

c^2=a^2+b^2

where

c is the greater side (the hypotenuse)

a and b are the legs

we have

a=3.7\ Km ----> the height of the airplane

c=14.2\ Km ---> slant distance from the airport

substitute

14.2^2=3.7^2+b^2

solve for b

b^2=14.2^2-3.7^2

b^2=187.95

b=\sqrt{187.95}\ Km

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A company has a budget of $280,000 for computing equipment. Tablets cost $500 each, laptops cost $2000 each, and servers cost $5
Kazeer [188]

Answer:

The number of tablets  200

the number of laptops  40

and, the number of servers 20

Step-by-step explanation:

Let the number of tablets be 'x'

the number of laptops be 'y'

and, the number of servers be 'z'

According to the given question

Total budget = $280,000

Tablets cost = $500 each

laptops cost = $2000 each

servers cost = $5000 each

Thus,

500x + 2000y + 5000z = 280,000 ..............(1)

also,

x = 5y  ................(2)

and,

y = 2z  

or

z = \frac{\textup{y}}{\textup{2}}   ............(3)

substituting y from 2 and 3 in equation 1,  we get

(500 × 5y) + (2000 × y) + (5000 × \frac{\textup{y}}{\textup{2}} ) = 280,000

or

2500y + 2000y + 2500y = 280,000

or

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or

y = 40

substituting y in equation 2, we get

x = 5 × 40 = 200

substituting y in equation 3 we get

z = \frac{\textup{40}}{\textup{2}}

or

z = 20

hence,

the number of tablets  200

the number of laptops  40

and, the number of servers 20

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3 years ago
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