Since x³ = x^(1/3) you can say that
(x¹⁰)^(1/3) = x^10/3 = x^(3 + 1/3) =
x³ ·∛x
The answer to the question is d
123a
123q
123w
123e
123r
123t
123y
123u
123i
123o
123p
123s
123d
123f
123g
123h
123j
123k
I thought this would be easy lol, I tried, sorry for not getting an answer
