Continuing from the setup in the question linked above (and using the same symbols/variables), we have
The next part of the question asks to maximize this result - our target function which we'll call
- subject to
.
We can see that
is quadratic in
, so let's complete the square.
Since
are non-negative, it stands to reason that the total product will be maximized if
vanishes because
is a parabola with its vertex (a maximum) at (5, 25). Setting
, it's clear that the maximum of
will then be attained when
are largest, so the largest flux will be attained at
, which gives a flux of 10,800.
Answer:
A. 20
Step-by-step explanation:
because she has twice as many and if you have twice as many then you'll have 40 so 40+20=60
Answer:
D'G' = 52.5 units
Step-by-step explanation:
Since the dilatation is centred at the origin then multiply the original coordinates by the scale factor 3.5
D' = (1 × 3.5, 7 × 3.5 ) = (3.5, 24.5 )
G' = (- 8 × 3.5, - 5 × 3.5 ) = (- 28, - 17.5 )
Calculate D'G' using the distance formula
d =
with (x₁, y₁ ) = D' (3.5, 24.5) and (x₂, y₂ ) = G' (- 28, - 17.5)
D'G' =
=
=
=
= 52.5 units
Answer:
I think you forgot part of the question
Step-by-step explanation:
Answer:
204 ft^2
Step-by-step explanation:
<u>triangle on the left</u>:
A= l x w x 1/2
A = 12 x 5 x 1/2
A = 30 ft^2
<u>triangle on the right</u>:
Same thing
A = 30 ft^2
<u>square in the middle</u>:
A = l x w
A = 12 x 12
A = 144 ft^2
<u>Add them up</u>:
30 + 30 + 144 = 204 ft^2