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klio [65]
3 years ago
7

SOMEONE PLEASE HELP ME ASAP PLEASE!!!​

Mathematics
1 answer:
andriy [413]3 years ago
3 0

<em>answer \\ (2 ,1) \\ please \: see \: the \: attached \: picture \:  \\ for \: full \: solution  \\ hope \: it \: helps</em>

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One liter of paint covers 100 square feet. How many gallons of paint does it take to cover a room whose walls have an area of 80
mezya [45]
1 gallon is 3.78 L
100 sq feet needs 1 L
800 sq feet needs x

100/800 = 1/x
100x = 800
x = 800/100
x = 8 L

If you use the fact that 4 L = 1 gallon then you need 2 gallons of paint. I you use the more accurate 3.78 L then
1 gallon = 3.78 L
x gallon = 8 L

3.78 x = 8*1
x = 8/3.78
x = 2.12 gallons.
 
I guess you could say that 1 gallon and 1 L would do you.
8 0
3 years ago
A triangular prism container is full of water of 428 cubic cm. The water is 10 cm deep, what is the base area of the container?
Hatshy [7]
<h3>The base area of triangular prism container is 42.8 cubic centimeter</h3>

<em><u>Solution:</u></em>

<em><u>The volume of triangular prism is given as:</u></em>

v = base\ area \times height

Given that,

A triangular prism container is full of water of 428 cubic cm

The water is 10 cm deep

Therefore,

v = 428 cubic cm

h = 10 cm

<em><u>Substituting the values we get,</u></em>

428 = base\ area \times 10\\\\base\ area = \frac{428}{10}\\\\base\ area = 42.8\ cm^2

Thus the base area of triangular prism container is 42.8 cubic centimeter

3 0
3 years ago
Expansion Numerically Impractical. Show that the computation of an nth-order determinant by expansion involves multiplications,
posledela

Answer:

  • number of multiplies is n!
  • n=10, 3.6 ms
  • n=15, 21.8 min
  • n=20, 77.09 yr
  • n=25, 4.9×10^8 yr

Step-by-step explanation:

Expansion of a 2×2 determinant requires 2 multiplications. Expansion of an n×n determinant multiplies each of the n elements of a row or column by its (n-1)×(n-1) cofactor determinant. Then the number of multiplies is ...

  mpy[n] = n·mp[n-1]

  mpy[2] = 2

So, ...

  mpy[n] = n! . . . n ≥ 2

__

If each multiplication takes 1 nanosecond, then a 10×10 matrix requires ...

  10! × 10^-9 s ≈ 0.0036288 s ≈ 0.004 s . . . for 10×10

Then the larger matrices take ...

  n=15, 15! × 10^-9 ≈ 1307.67 s ≈ 21.8 min

  n=20, 20! × 10^-9 ≈ 2.4329×10^9 s ≈ 77.09 years

  n=25, 25! × 10^-9 ≈ 1.55112×10^16 s ≈ 4.915×10^8 years

_____

For the shorter time periods (less than 100 years), we use 365.25 days per year.

For the longer time periods (more than 400 years), we use 365.2425 days per year.

8 0
3 years ago
What is the sum of -1/11 and -5/11<br> A. 4/11<br> B. 6/11<br> C. -4/11<br> D. -6/11
saw5 [17]
Itshould be 6/11 sorry if it’s wrongg
3 0
3 years ago
Read 2 more answers
Tom and jasper have the same percentage of blue marbles in their bags of marble tom has 5 blue marbles and 20 total marbles jasp
Lesechka [4]
8 of them are not blue
6 0
3 years ago
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