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ch4aika [34]
3 years ago
13

In a class of 64 students, each students offers Physics or Math or both. If 50 students offers Math and the number of students w

ho offered Math only is twice the number of students offering Physics. How many students offered both subjects ​
Mathematics
1 answer:
Debora [2.8K]3 years ago
6 0

Answer:

 tZsxdfgh

Step-by-step explanation:

   uidfghj

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The steps below show the incomplete solution to find the value of x for the
Anna35 [415]
Just add 4 on both sides then divide both sides by 4 and then you’ll get your answer. I hope that helps!
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jo divides a rectangle into parts. each part is 1/4 the area of the whole rectagle. how many parys did ko divide the rectanhle i
meriva
Jo divided the rectangle into 4 parts if each part is 1/4 of the whole rectangle. 4 is the denominator which is the number of parts that has been divided.
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PLEASE HELP ME MY HOMEWORK IS DUE TODAY!! IF YOU ANSWER IT RIGHT ILL MARK YOU BRAINLIEST!!
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HELP 100 POINTS The population of a city is modeled with the function P=250,000e^0.013t​, where t is the number of years since 2
erma4kov [3.2K]
Pretty difficult problem, but that’s why I’m here.
First we need to identify what we’re looking for, which is t. So now plug 450k into equation and solve for t.
450000 = 250000e^0.013t
Now to solve this, we need to remember this rule: if you take natural log of e you can remove x from exponent. And natural log of e is 1.
Basically ln(e^x) = xln(e) = 1*x
So knowing this first we need to isolate e
450000/250000 = e^0.013t
1.8 = e^0.013t
Now take natural log of both
Ln(1.8) = ln(e^0.013t)
Ln(1.8) = 0.013t*ln(e)
Ln(1.8) = 0.013t * 1
Now solve for t
Ln(1.8)/0.013 = t
T= 45.21435 years
Now just to check our work plug that into original equation which we get:
449999.94 which is basically 500k (just with an error caused by lack of decimals)
So our final solution will be in the 45th year after about 2 and a half months it will reach 450k people.
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2 years ago
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