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Thepotemich [5.8K]
3 years ago
11

19. Marianna wants to buy a new tennis racket that

Mathematics
1 answer:
Tema [17]3 years ago
7 0

Answer:

11 weeks

Step-by-step explanation:

30-8=22

22/2= 11

You might be interested in
Days/ cost to rent a truck 1/34 2/50 3/66 4/82 A/ C=16d B/ C= 16d + 18 C/ C= 16d + 16 D/ C=18d + 16
Mamont248 [21]
Use the given information as (x, y) points.
You have
(1, 34)
(2, 50)
(3, 66)
(4, 82)
The difference between renting for 1 day and 2 days is 50 - 34 = 16.
The difference between renting for 2 days and 3 days is 66 - 50 = 16
The difference between renting for 3 days and 4 days is 82 - 66 = 16
For each day you rent you pay $16.
Now look at renting for 1 day.
The rental for 1 day is $16, but for 1 day you pay $34.
$34 - $16 = $18
There is an extra $18 in the rental for every day. The $18 is fixed.
That means, to rent a truck, you must pay a fixed amount of $18 plus $16 per day.

total cost = daily cost + fixed cost
total cost =       16d    +      16
c = 16d + 18
3 0
3 years ago
Read 2 more answers
Given points A(-1, -2) and B(2, 4) where AP: BP=1:2, find the locus of point P.​
koban [17]

Answer:

x^2 + 4x + y^2 +8y  =  0

Step-by-step explanation:

Given

A = (-1,-2)

B = (2,4)

AP:BP = 1 : 2

Required

The locus of P

AP:BP = 1 : 2

Express as fraction

\frac{AP}{BP} = \frac{1}{2}

Cross multiply

2AP = BP

Calculate AP and BP using the following distance formula:

d = \sqrt{(x - x_1)^2 + (y - y_1)^2}

So, we have:

2 * \sqrt{(x - -1)^2 + (y - -2)^2} = \sqrt{(x - 2)^2 + (y - 4)^2}

2 * \sqrt{(x +1)^2 + (y +2)^2} = \sqrt{(x - 2)^2 + (y - 4)^2}

Take square of both sides

4 * [(x +1)^2 + (y +2)^2] = (x - 2)^2 + (y - 4)^2

Evaluate all squares

4 * [x^2 + 2x + 1 + y^2 +4y + 4] = x^2 - 4x + 4 + y^2 - 8y + 16

Collect and evaluate like terms

4 * [x^2 + 2x + y^2 +4y + 5] = x^2 - 4x + y^2 - 8y + 20

Open brackets

4x^2 + 8x + 4y^2 +16y + 20 = x^2 - 4x + y^2 - 8y + 20

Collect like terms

4x^2 - x^2 + 8x + 4x + 4y^2 -y^2 +16y + 8y  + 20 - 20 =  0

3x^2 + 12x + 3y^2 +24y  =  0

Divide through by 3

x^2 + 4x + y^2 +8y  =  0

3 0
3 years ago
Write an inequality for the graph<br> A. x &gt; -3<br> B. x &lt; -3<br> c. x &gt; -3<br> _
earnstyle [38]

Answer:

A. x > -3

Step-by-step explanation:

Well by looking at the graph we can tell that,

the line we can tell that the line goes to the right of of the number line,

Meaning x is greater than -3.

<em>Thus,</em>

<em>x > -3.</em>

<em />

<em>Hope this helps :)</em>

5 0
3 years ago
Divide the number 20 into two parts (not necessarily integers) in a way that makes the product of one part with the square of th
Ilya [14]

Answer:

13 1/3 and  6 2/3.

Step-by-step explanation:

Let the 2 parts be x and (20 - x).

So x^2(20 - x) must be a maximum.

y = x^2(20 - x)

y = 20x^2 - x^3

Finding the derivative):

y' =  40x - 3x^2 = 0   for  maxm/minm value.

x( 40 - 3x) = 0

40 - 3x = 0

3x = 40

x = 40/3.

This is a maximum because the second derivative y" =  40 - 6x = 40 - 6(40/3)) is negative.

So the 2 numbers are 13 1/3 and  6 2/3.

3 0
2 years ago
The GCF of two numbers is 850 neither number is divisible by the other what is the smallest these two numbers can be?
saul85 [17]
Began by dividing 850 by 1, then 2, then 3, and so on, and I made a list of the whole numbers.

They were 1, 2, 5, 10, 17, 25, 34, 50, 85, 170, 425, and 850

By inspection, the two smallest numbers which when multiplied together yielded 850 were 25 and 34.
5 0
2 years ago
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