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jekas [21]
4 years ago
15

Find value of x, show your work

Mathematics
1 answer:
Zina [86]4 years ago
5 0
Here is your answer

\huge x=\frac{35}{2}cm= 17.5cm

REASON :
AB//CD

So,

/_A=/_D ... (alternate int. angles)

/_B=/_C ... (alt. int. angles)

So,

Tri.ABE~Tri.DCE... (by AA similarity)

Therefore,

Corresponding sides are proportional

i.e.

\frac{AE}{DE}=\frac{AB}{DC}

\frac{5}{x}=\frac{4}{14}

x=\frac{5×14}{4}

x=\frac{5×7}{2}

x=\frac{35}{2}

HOPE IT IS USEFUL
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In a right triangle, if the length of the hypotenuse is 39 and the length of one of the other sides is 15, what is the length of
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3 years ago
Of 900 centimeters. The table shows the height of each bounce.
Mars2501 [29]

Answer:

  • <u><em>Rounding to nearest tenth of centimeter, the ball bounces 192.1 cm high on the 5th bounce.</em></u>

<u><em></em></u>

Explanation:

The <em>ball is dropped from a height of 900 centimeters</em>.

Since the heights form a <em>geometric sequence,</em> you can find a common ratio between consecutive terms. This is:

  • Height bounce 2 / height bounce 1 = 560 / 800 = 0.7
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Hence, the ratio of the geometric sequence is 0.7, and taking bounce 1 as the start of the sequence, the general term of the sequence is:

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With that formula you can find any term:

             n=1,a_1=800(0.7)^{(1-1)}=800(0.7)^0=800\\ \\ n=2,a_{2}=800(0.7)^{(2-1)}=800(0.7)=560\\ \\n=5,a_{5}=800(0.7)^{(5-1)}=800(0.4)^4=192.08

Rounding to <em>nearest tenth of centimeter</em>, the ball bounces 192.1 cm high on the 5th bounce.

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4 years ago
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Answer:

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3 years ago
Read 2 more answers
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