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3 years ago

Find value of x, show your work

Mathematics

1 answer:

Zina [86]3 years ago

5 0

Here is your answer

$\huge x=\frac{35}{2}cm= 17.5cm$

REASON :
AB//CD

So,

/_A=/_D ... (alternate int. angles)

/_B=/_C ... (alt. int. angles)

So,

Tri.ABE~Tri.DCE... (by AA similarity)

Therefore,

Corresponding sides are proportional

i.e.

$\frac{AE}{DE}=\frac{AB}{DC}$

$\frac{5}{x}=\frac{4}{14}$

$x=\frac{5×14}{4}$

$x=\frac{5×7}{2}$

$x=\frac{35}{2}$

HOPE IT IS USEFUL

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Explain how you can round 25.691 to the greatest place.

labwork [276]

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How do I solve <br>y=sin1/2(x+pi/4)

dexar [7]

Answer:

x = 2 csc(1) y - π/4

Step-by-step explanation:

Solve for x:

y = 1/2 sin(1) (x + π/4)

y = 1/2 (x + π/4) sin(1) is equivalent to 1/2 (x + π/4) sin(1) = y:

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4 years ago

Try the numbers 22, 23, 24, 25 in the equation 4/3 = 32/d to test whether any of them is a solution. a. 23 is a solution. c. 24

S_A_V [24]

Answer:

c. 24 is a solution

Step-by-step explanation:

Given equation:

$\frac{4}{3}=\frac{32}{d}$

To test the numbers 22, 23, 24, 25 for the solution.

Solution:

In order to test the given number for the solution, we will plugin each number in the unknown variable $d$ and see if it satisfies the equation.

1) $d=22$

$\frac{4}{3}=\frac{32}{22}$

Reducing fraction to simplest form by dividing the numerator and denominator by their G.C.F.

$\frac{4}{3}=\frac{32\div 2}{22\div 2}$

$\frac{4}{3}=\frac{16}{11}$

The above statement can never be true and hence 22 is not a solution.

2) $d=23$

$\frac{4}{3}=\frac{32}{23}$

The fractions can no further be reduced.

The statement can never be true and hence 23 is not a solution.

3) $d=24$

$\frac{4}{3}=\frac{32}{24}$

Reducing fraction to simplest form by dividing the numerator and denominator by their G.C.F.

$\frac{4}{3}=\frac{32\div 8}{24\div 8}$

$\frac{4}{3}=\frac{4}{3}$

The above statement is always true and hence 24 is a solution.

4) $d=25$

$\frac{4}{3}=\frac{32}{25}$

The fractions can no further be reduced.

The statement can never be true and hence 25 is not a solution.

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3 years ago

At the end of each week, an employer gives some vacation hours to a few randomly selected employees. There are 25 employees in h

densk [106]

Answer: There are 177100 possible groups.

Step-by-step explanation:

Given: Total employees = 25

Number of employees wants to choose = 6

The combination of n things taken r at a time is given by:-

$^nC_r=\frac{n!}{r!(n-r)!}$

Put n = 25 and r= 6, we get

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3 years ago

How do you solve these

IRINA_888 [86]

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