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3 years ago

13

Compared to yellow light, orange light has A. a shorter wavelength. B. a wavelength closer to that of gamma rays. C. the same fr

equency. D. a longer wavelength.

1 answer:

tankabanditka [31]3 years ago

7 0

D. A longer Wavelength

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3. an observer is at the midpoint between two coherent in-phase sources of sound of frequency 780 hz. what is the minimum distan

baherus [9]

Answer:

Explanation:

wavelength of sound = velocity / frequency

= 340 / 780

= .4359 m

Let the observer be at equal distance d from in phase source .

let it moves by distance x for destructive interference .

path difference from source

= d + x - (d - x )

= 2x

for destructive interference

path difference = wave length / 2

2x = .4359 / 2 m

x = .4359 / 4

= .108975 m

10.9 cm

so observer must move by distance 10.9 cm towards on of the centers.

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3 years ago

The weight of a person is 500N and his foot imprint area is 0.5m^2.Calculate the total pressure exerted by person when he stands

Ghella [55]

Answer:

Pressure on both feet will be $500N/m^2$

Explanation:

Weight of the person F = 500 N

Area of foot print $A=0.5m^2$

Area of both the foot $A=2\times 0.5=1m^2$

We have to find pressure on both the feet

Pressure is equal to ratio of force and area

So pressure $P=\frac{F}{A}$

$P=\frac{500}{1}=500N/m^2$

So the pressure on both feet will be $500N/m^2$ when person stands on both feet.

7 0

3 years ago

What is the natural pH of the ocean?

Katyanochek1 [597]

Answer: Basic

Explanation: water is "neutral" with a ph of 7, the ocean has like 8 so it is more basic on the scale

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3 years ago

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All ions are atoms with a

Cloud [144]

All ions are atoms with a charge

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4 years ago

Radio waves from an fm station have a frequency of 103.1 mhz. if the waves travel with a speed of 3.00 ´ 10 m/s, what is the wav

ryzh [129]

The frequency of the radio waves from the fm station is:
$f=103.1 MHz = 103.1 \cdot 10^6 Hz$
And the speed of the waves corresponds to the speed of light:
$v=3 \cdot 10^8 m/s$
Therefore, the wavelength of the radio waves can be found by using the following equation:
$\lambda= \frac{v}{f}= \frac{3 \cdot 10^8 m/s}{103.1 \cdot 10^6 Hz}=2.91 m$

3 0

3 years ago