Answer:
The longer the length of string, the farther the pendulum falls; and therefore, the longer the period, or back and forth swing of the pendulum. The greater the amplitude, or angle, the farther the pendulum falls; and therefore, the longer the period.
Explanation:
Answer:
182.9 Volts
Explanation:
R = resistance of the resistor = 50 Ω
C = capacitance of the capacitor = 200 μF = 200 x 10⁻⁶ F
L = Inductance of the inductor = 120 mH = 0.12 H
f = frequency = 60 Hz
Capacitive reactance is given as
X = (2πfC)⁻¹
X = (2(3.14) (60) (200 x 10⁻⁶))⁻¹
X = 13.3 Ω
Inductive reactance is given as
X' = 2πfL
X' = 2(3.14) (60) (0.12)
X' = 45.2 Ω
Impedance of the circuit is given as
z = √(R² + (X' - X)²)
z = √(50² + (45.2 - 13.3)²)
z = 59.31 Ω
V = rms emf of the source = 240 Volts
rms voltage across the inductor is given as
V' = V z⁻¹ X'
V' = (240) (59.31)⁻¹ (45.2)
V' = 182.9 Volts
QUESTION: A pure jet engine propels and aircraft at 340 m/s through air at 45 kPa and -13C. The inlet diameter of this engine is 1.6 m, the compressor pressure ratio is 13, and the temperature at the turbine inlet is 557C. Determine the velocity at the exit of this engines nozzle and the thrust produced.
ANSWER: Due to the propulsion from the inlet diameter of this engine bring 1.6 m allows the compressor rations to radiate allowing thrust propultion above all velocitic rebisomes.
Answer:
h = 4271.43 m
Explanation:
given,
Volume of the water = 1 m³
temperature decrease by = 10°C
heat removed from water
Q = m c ΔT
Q = ρ V c ΔT
= 1000 × 1 × 4186 × 10
= 4.186 × 10⁷ J
energy is used to do work to move the water against its weight
Q = force × displacement
4.186 × 10⁷ J = m g × h
4.186 × 10⁷ J = 1000 × 1 × 9.8 × h
h = 4271.43 m
hence, the change in height of is equal to h = 4271.43 m
<span>A current i travels counterclockwise through a closed copper wire loop which has the shape of a rectangle with sides</span>
