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Alexxandr [17]
3 years ago
12

Two students were asked if they liked to read. Is this a good example of a statistical question? Why or why not?

Mathematics
1 answer:
professor190 [17]3 years ago
7 0

Answer:

Yes, this is a good statistical question because a variety of answers are given.

Step-by-step explanation:

A question can be called a good statistical question because of the variety of the answers it can bring to data. The answers to the same question will be different for different people.

Hence,

Yes, this is a good statistical question because a variety of answers are given ..

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What is the longest side of a right triangle?
frozen [14]
The longest side of a right triangle is hypotenuse
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3 years ago
If T equals 1 / r + 1 / s equals r + S over RS, then what is 1 / T in terms of R&S?
Thepotemich [5.8K]
T=\dfrac{1}{r}+\dfrac{1}{s}\\\\T=\dfrac{1\cdot s}{r\cdor s}+\dfrac{1\cdot r}{r\cdot s}\\\\T=\dfrac{s}{rs}+\dfrac{r}{rs}\\\\T=\dfrac{s+r}{rs}\to\dfrac{1}{T}=\dfrac{rs}{s+r}
7 0
3 years ago
You wonder how many cars there are in your area. You call up the Ford dealership and ask how many Fords they’ve sold. They repor
SVETLANKA909090 [29]
If we take 1200 as the 100%, how much percentage is 700 of it?

well \bf \begin{array}{ccllll}
amount&\%\\
\textendash\textendash\textendash\textendash\textendash\textendash&\textendash\textendash\textendash\textendash\textendash\textendash\\
1200&100\\
700&x
\end{array}\implies \cfrac{1200}{700}=\cfrac{100}{x}\implies x=\cfrac{700\cdot 100}{1200}
\\\\\\
x=\cfrac{175}{3}

so, (175/3)% or roughly 58.3%

now, how much is (175/3)% of 15000 ?
well, if we take 15000 as the 100%
then   \bf \begin{array}{ccllll}
amount&\%\\
\textendash\textendash\textendash\textendash\textendash\textendash&\textendash\textendash\textendash\textendash\textendash\textendash\\
15000&100\\
x&\frac{175}{3}
\end{array}\implies \cfrac{15000}{x}=\cfrac{100}{\frac{175}{3}}
\\\\\\
\cfrac{15000\cdot \frac{175}{3}}{100}=x\implies \cfrac{5000\cdot 175}{100}=x
6 0
3 years ago
Assume the readings on thermometers are normally distributed with a mean of 0°C and a standard deviation of 1.00°C. Find the pro
lisov135 [29]

Answer:

0.0326 = 3.26% probability that a randomly selected thermometer reads between −2.23 and −1.69.

The sketch is drawn at the end.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean of 0°C and a standard deviation of 1.00°C.

This means that \mu = 0, \sigma = 1

Find the probability that a randomly selected thermometer reads between −2.23 and −1.69

This is the p-value of Z when X = -1.69 subtracted by the p-value of Z when X = -2.23.

X = -1.69

Z = \frac{X - \mu}{\sigma}

Z = \frac{-1.69 - 0}{1}

Z = -1.69

Z = -1.69 has a p-value of 0.0455

X = -2.23

Z = \frac{X - \mu}{\sigma}

Z = \frac{-2.23 - 0}{1}

Z = -2.23

Z = -2.23 has a p-value of 0.0129

0.0455 - 0.0129 = 0.0326

0.0326 = 3.26% probability that a randomly selected thermometer reads between −2.23 and −1.69.

Sketch:

3 0
3 years ago
Just help me already plzzzzzzzzzzzz
laila [671]

Answer:

140-80= 60

60/5=12

so B 12 is the answer

4 0
2 years ago
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