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Nataly_w [17]
3 years ago
5

You wonder how many cars there are in your area. You call up the Ford dealership and ask how many Fords they’ve sold. They repor

t that they’ve sold a total of 15,000 cars. You then take a lawn chair and camp out on a busy road and count cars. You count 1200 cars and note that 700 of them are Fords. Estimate the number of cars in your area.
Mathematics
1 answer:
SVETLANKA909090 [29]3 years ago
6 0
If we take 1200 as the 100%, how much percentage is 700 of it?

well \bf \begin{array}{ccllll}
amount&\%\\
\textendash\textendash\textendash\textendash\textendash\textendash&\textendash\textendash\textendash\textendash\textendash\textendash\\
1200&100\\
700&x
\end{array}\implies \cfrac{1200}{700}=\cfrac{100}{x}\implies x=\cfrac{700\cdot 100}{1200}
\\\\\\
x=\cfrac{175}{3}

so, (175/3)% or roughly 58.3%

now, how much is (175/3)% of 15000 ?
well, if we take 15000 as the 100%
then   \bf \begin{array}{ccllll}
amount&\%\\
\textendash\textendash\textendash\textendash\textendash\textendash&\textendash\textendash\textendash\textendash\textendash\textendash\\
15000&100\\
x&\frac{175}{3}
\end{array}\implies \cfrac{15000}{x}=\cfrac{100}{\frac{175}{3}}
\\\\\\
\cfrac{15000\cdot \frac{175}{3}}{100}=x\implies \cfrac{5000\cdot 175}{100}=x
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Advertising expenses are a significant component of the cost of goods sold. Listed below is a frequency distribution showing the
Alexxandr [17]

Answer:

Step-by-step explanation:

The table can be computed as:

Advertising Expenses ($ million)     Number of companies

25 up to 35                                                    4

35 up to 45                                                    19

45 up to 55                                                    27

55 up to 65                                                    16

65 up to 75                                                     9

TOTAL                                                            75

Let's find the probabilities first:

P(25 - 35) = P \Big(\dfrac{25-50.93}{10.80}

For 35 up to 45

P(35 - 45) = P \Big(\dfrac{35-50.93}{10.80}

For 45 up to 55

P(45 - 55) = P \Big(\dfrac{45-50.93}{10.80}

For 55 up to 65

P(55 - 65) = P \Big(\dfrac{55-50.93}{10.80}

For 65 up to 75

P(65 - 75) = P \Big(\dfrac{65-50.93}{10.80}

Chi-Square Table can be computed as follows:

Expense   No of   Probabilities(P)  Expe                (O-E)^2   \dfrac{(O-E)^2}{E}

             compa                                 cted E (n*p)

             nies (O)  

25-35           4      0.0612    75*0.0612 = 4.59        0.3481       0.0758

35-45           19     0.2218   75*0.2218 = 16.635     5.5932       0.3362

45-55           27     0.3568   75*0.3568 = 26.76     0.0576      0.021

55-65           16      0.2552   75*0.2552 = 19.14      9.8596      0.5151

65-75           9      0.0839     75*0.0839 = 6.2925   7.331         1.1650

                                                                                           \sum \dfrac{(O-E)^2}{E}= 2.0492                                                                                                      

Using the Chi-square formula:

X^2 = \dfrac{(O-E)^2}{E} \\ \\ Chi-square  \ X^2 = 2.0942

Null hypothesis:

H_o: \text{The population of advertising expenses follows a normal distribution}

Alternative hypothesis:  

H_a: \text{The population of advertising expenses does not follows a normal distribution}

Assume that:

\alpha = 0.02

degree of freedom:

= n-1

= 5 -1

= 4

Critical value from X^2 = 11.667

Decision rule: To reject H_o  \  if \  X^2  test statistics is greater than X^2 tabulated.

Conclusion: Since X^2 = 2.0942 is less than critical value 11.667. Then we fail to reject H_o

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The table shows the breakdown of the points scored in last week's basketball game.
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Answer:

a. Total field goal points scored in the first two quarters, in simplest linear expression form is: 3x - 4.

b. The total points scored in the game, in simplest linear expression form is: 6x - 1.

a. The goal points scored in the first two quarters are expressed in linear forms as: 2x - 6 and x + 2.

The total field goal points in the first two quarters = 2x - 6 + x + 2

Add like terms

3x - 4

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Add like terms and simplify the expression

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