Answer:
Therefore, the probability is P=0.000064.
Step-by-step explanation:
We know that a pressure control apparatus contains 3 electronic tubes. The apparatus will not work unless all tubes are operative. If the probability of failure of each tube during some interval of time is 0.04.
We calculate the probability of failure of the apparatus.
We get:
Therefore, the probability is P=0.000064.
Answer:
In the interval of - 2 ≤ t ≤ 4, the average rate of change is zero.
Step-by-step explanation:
The function is given to be ............ (1)
(i) Now, for 1 ≤ t ≤ 4, we will put t = 1 and t = 4.
So, g(1) = 5, g(4) = - 4. {From equation (1)}
Hence, g(1) ≠ g(4)
(ii) Now, for - 4 ≤ t ≤ - 3, we will put t = - 4 and t = - 3.
So, g(- 4) = - 20, g(- 3) = - 11. {From equation (1)}
Hence, g(- 4) ≠ g(- 3)
(iii) Now, for -2 ≤ t ≤ 0, we will put t = - 2 and t = 0.
So, g(- 2) = - 4, g(0) = 4. {From equation (1)}
Hence, g(- 2) ≠ g(0)
(iv) Now, for - 2 ≤ t ≤ 4, we will put t = - 2 and t = 4.
So, g(- 2) = - 4, g(4) = - 4. {From equation (1)}
Hence, g(- 2) = g(4)
Therefore, in the interval of - 2 ≤ t ≤ 4, the average rate of change is zero. (Answer)