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4 years ago

14

HELP ME ILL GIVE BRAINLIST!!

2 answers:

alexandr1967 [171]4 years ago

7 0

Answer:

12

Step-by-step explanation:

answer is 12

Anna11 [10]4 years ago

3 0

Answer:

d = 12

Step-by-step explanation:

<u>5</u> = <u>10</u>

6 d

just cross multiply:

5d = 60

d = 60/5

d = 12

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If x = 82°, find the measures of angles 1, 2, and 3

otez555 [7]

Answer:

98

Step-by-step explanation:

x(o) + 1(o) = 180(o)

∠2° = ∠x°

∠1° = ∠3°

6 0

3 years ago

Read 2 more answers

PLEASE HELP I PUT THE PROBLEM AS A PICTURE PLEASE ANSWER WILL GIVE 30 POINTS SHOW WORK

dem82 [27]

Answer:

$\huge\boxed{9}$

Step-by-step explanation:

$\sf (2^8 * 3^{-5} * 6^0)^{-2 } (\frac{3^{-2}}{2^3} )^4*2^{28}$

Rule of exponents $a^0 = 1$ , $1/a^m = a^{-m}$

=> $\sf 2^{8*-2} * 3 ^{-5*-2} * 3 ^{-2}* 2^{-3*4} * 2^{28}$

=> $\sf 2 ^ {-16} * 3^{10} * 3^{-8} * 2 ^{-12}* 2^{28}$

Combining same bases

=> $\sf 2 ^ {-16} * 2 ^{-12}* 2^{28}* 3^{10} * 3^{-8}$

When bases are same , powers are to be added

=> $\sf 2 ^{-16-12+28} * 3^{10-8}$

=> $\sf 2^{-28+28} * 3^2$

=> $\sf 2^0 * 3^2$

=> $\sf 3^2$

=> 9

8 0

3 years ago

Can someone please help on number 19. WILL MARK YOU AS BRAINIEST!!!

liraira [26]

Answer: the width is 150

Step-by-step explanation:

5 0

3 years ago

A poster board was cut into equal pieces, and 3 pieces were used for

AnnyKZ [126]

Answer: 8. There were 11 pieces and 3 were used, so 8 are left.

5 0

3 years ago

A ball is thrown into the air. The path it takes is modeled by the equation: -3t+24t = h, where t is the time in seconds and h i

astra-53 [7]

Given:

The given equation is:

$-3t^2+24t=h$

Where, t is the time in seconds and h is the height of the ball above the ground, measured in feet.

To find:

The inequality to model when the height of the ball is at least 36 feet above the ground. Then find time taken by ball to reach at or above 36 feet.

Solution:

We have,

$-3t^2+24t=h$

The height of the ball is at least 36 feet above the ground. It means $h\geq 36$ .

$-3t^2+24t\geq 36$

$-3t^2+24t-36\geq 0$

$-3(t^2-8t+12)\geq 0$

Splitting the middle term, we get

$-3(t^2-6t-2t+12)\geq 0$

$-3(t(t-6)-2(t-6))\geq 0$

$-3(t-2)(t-6)\geq 0$

The critical points are:

$-3(t-2)(t-6)=0$

$t=2,6$

These two points divide the number line in 3 intervals $(-\infty,2),(2,6),(6,\infty)$ .

Intervals Check point $-3(t-2)(t-6)\geq 0$ Result

$(-\infty,2)$ 0 $(-)(-)(-)=(-)$ False

$(2,6)$ 4 $(-)(+)(-)=+>0$ True

$(6,\infty)$ 8 $(-)(+)(+)=(-)$ False

The inequality is true for (2,6) and the sign of inequality is $\geq$ . So, the ball is above 36 feet between 2 to 6 seconds.

$6-2=4$

Therefore, the required inequality is $-3t^2+24t\geq 36$ and the ball is 36 feet above for 4 seconds.

3 0

3 years ago