Question

PLEASE HELP I PUT THE PROBLEM AS A PICTURE PLEASE ANSWER WILL GIVE 30 POINTS SHOW WORK

Answer 1

Answer:

$\huge\boxed{9}$

Step-by-step explanation:

$\sf (2^8 * 3^{-5} * 6^0)^{-2 } (\frac{3^{-2}}{2^3} )^4*2^{28}$

Rule of exponents $a^0 = 1$ , $1/a^m = a^{-m}$

=> $\sf 2^{8*-2} * 3 ^{-5*-2} * 3 ^{-2}* 2^{-3*4} * 2^{28}$

=> $\sf 2 ^ {-16} * 3^{10} * 3^{-8} * 2 ^{-12}* 2^{28}$

Combining same bases

=> $\sf 2 ^ {-16} * 2 ^{-12}* 2^{28}* 3^{10} * 3^{-8}$

When bases are same , powers are to be added

=> $\sf 2 ^{-16-12+28} * 3^{10-8}$

=> $\sf 2^{-28+28} * 3^2$

=> $\sf 2^0 * 3^2$

=> $\sf 3^2$

=> 9