2 years ago

Please help with no links.

Mathematics

1 answer:

Wewaii [24]2 years ago

5 0

Answer:

I think its B

I dont know if Im wrong

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Answer: $\sqrt[3]{125x^3}$ .

Step-by-step explanation: Given radical expression

$\sqrt[3]{5x} \times \sqrt[3]{25x^2}$ .

According to the product property of roots.

$\sqrt[n]{a} \times \sqrt[n]{b} = \sqrt[n]{a \times b}$

On applying above rule, we get

$\sqrt[3]{5x} \times \sqrt[3]{25x^2} = \sqrt[3]{5x \times 25x^2}$

5 × 25 = 125 and

$x \times x^2 = x^3$

Therefore,

$\sqrt[3]{5x \times 25x^2}= \sqrt[3]{125x^3}$

<h3>So, the correct option would be second option $\sqrt[3]{125x^3}$ .</h3>

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