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2 years ago

14

Which of the following is a polynomial?

1 answer:

maw [93]2 years ago

5 0

In mathematics, a polynomial is an expression consisting of variables (also called indeterminates) is called polynomial

i think by this definition you can find your answer by your self

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N circle Y, what is m∠1?<br> 6°<br> 25°<br> 31°<br> 37°

spayn [35]

Answer:

31

Step-by-step explanation:

add the 2 angles given

37 + 25 = 62

then take half of that 62/2 = 31

angle 1 = 31 degrees

3 0

3 years ago

Read 2 more answers

Is 7.0 a rational or a whole

anyanavicka [17]

Whole number because 7 is in front of the deciaml point

4 0

2 years ago

Read 2 more answers

1. What is the spinning mo tion of the earth called? = rotation

Tasya [4]

Answer:

<u><em>Rotation and Revolution are two motions of the earth.</em></u>

Step-by-step explanation:

The description is in the image below:

5 0

2 years ago

Please help me for the love of God if i fail I have to repeat the class

Elena-2011 [213]

$\theta$ is in quadrant I, so $\cos\theta>0$ .

$x$ is in quadrant II, so $\sin x>0$ .

Recall that for any angle $\alpha$ ,

$\sin^2\alpha+\cos^2\alpha=1$

Then with the conditions determined above, we get

$\cos\theta=\sqrt{1-\left(\dfrac45\right)^2}=\dfrac35$

and

$\sin x=\sqrt{1-\left(-\dfrac5{13}\right)^2}=\dfrac{12}{13}$

Now recall the compound angle formulas:

$\sin(\alpha\pm\beta)=\sin\alpha\cos\beta\pm\cos\alpha\sin\beta$

$\cos(\alpha\pm\beta)=\cos\alpha\cos\beta\mp\sin\alpha\sin\beta$

$\sin2\alpha=2\sin\alpha\cos\alpha$

$\cos2\alpha=\cos^2\alpha-\sin^2\alpha$

as well as the definition of tangent:

$\tan\alpha=\dfrac{\sin\alpha}{\cos\alpha}$

Then

1. $\sin(\theta+x)=\sin\theta\cos x+\cos\theta\sin x=\dfrac{16}{65}$

2. $\cos(\theta-x)=\cos\theta\cos x+\sin\theta\sin x=\dfrac{33}{65}$

3. $\tan(\theta+x)=\dfrac{\sin(\theta+x)}{\cos(\theta+x)}=-\dfrac{16}{63}$

4. $\sin2\theta=2\sin\theta\cos\theta=\dfrac{24}{25}$

5. $\cos2x=\cos^2x-\sin^2x=-\dfrac{119}{169}$

6. $\tan2\theta=\dfrac{\sin2\theta}{\cos2\theta}=-\dfrac{24}7$

7. A bit more work required here. Recall the half-angle identities:

$\cos^2\dfrac\alpha2=\dfrac{1+\cos\alpha}2$

$\sin^2\dfrac\alpha2=\dfrac{1-\cos\alpha}2$

$\implies\tan^2\dfrac\alpha2=\dfrac{1-\cos\alpha}{1+\cos\alpha}$

Because $x$ is in quadrant II, we know that $\dfrac x2$ is in quadrant I. Specifically, we know $\dfrac\pi2$ , so $\dfrac\pi4$ . In this quadrant, we have $\tan\dfrac x2>0$ , so

$\tan\dfrac x2=\sqrt{\dfrac{1-\cos x}{1+\cos x}}=\dfrac32$

8. $\sin3\theta=\sin(\theta+2\theta)=\dfrac{44}{125}$

6 0

3 years ago

Please ASAP please

Mars2501 [29]

Answer:

A)3.125hr

B)53.325mi

Step-by-step explanation:

speed=distance/time

an hour and 15min=1.25hr

32/1.25=25.6mi/hr

80/25.6=3.125hr

B)

2hr and 5min=2+5/60=2.083hr

2.083x25.6=53.325mile

7 0

2 years ago