What is the volume of a figure that is 9 inches wide, 3 inches tall and 3 inches long?

Mathematics

1 answer:

motikmotik3 years ago

5 0

Answer:

1/2

Step-by-step explanation:

1/2 of an answer is zero answer

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Please explain your answer

Irina18 [472]

$\text{Distance = } \sqrt{(5 + 8)^2+ (-3 + 3)^2 }= \sqrt{13^2} = 13$

Answer: 13 units

6 0

3 years ago

A hemispherical bowl of radius 5 inches is filled to a depth of h inches, where 0less than or equalshless than or equals5. Find

mestny [16]

The shape of the water is that of a "spherical cap." The formula for the volume of a spherical cap is ...

... V = π·h²·(r -h/3) . . . . . . . from web search

For a radius of 5 in, this is

... V = π·h²·(5 -h/3) . . . . in³

_____

For h=0

... V = π·0²·(5 -0/3) = 0

For h=5 in

... V = π·(5 in)²·((5 -5/3) in) = (2/3)π·5³ in³ . . . . . the volume of a hemisphere of radius 5

4 0

3 years ago

Write an equation of a line that is perpendicular to the line y=2/3x and passes through origin

sesenic [268]

keeping in mind that perpendicular lines have negative reciprocal slopes, hmmm what's the slope of the equation above anyway?

$\bf y = \cfrac{2}{3}x\implies y = \stackrel{\stackrel{m}{\downarrow }}{\cfrac{2}{3}}x+0\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array} \\\\[-0.35em] ~\dotfill$

$\bf \stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}} {\stackrel{slope}{\cfrac{2}{3}}\qquad \qquad \qquad \stackrel{reciprocal}{\cfrac{3}{2}}\qquad \stackrel{negative~reciprocal}{-\cfrac{3}{2}}}$

so we're really looking for the equation of a line whose slope is -3/2 and runs through (0,0).

$\bf (\stackrel{x_1}{0}~,~\stackrel{y_1}{0})~\hspace{10em} \stackrel{slope}{m}\implies -\cfrac{3}{2} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{0}=\stackrel{m}{-\cfrac{3}{2}}(x-\stackrel{x_1}{0})\implies y=-\cfrac{3}{2}x$