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tino4ka555 [31]
3 years ago
13

Solve 6(x-7)=10(x+4) for x

Mathematics
2 answers:
Veseljchak [2.6K]3 years ago
8 0
6x - 42 = 10x + 40
6x - 82 = 10x
-82 = 4x
-82 / 4 = -20.5
x = -20.5

6(-20.5 - 7) = -165
10(-20.5 + 4) = -165


Ksenya-84 [330]3 years ago
3 0
6(x-7)=10(x+4)
6x-42=10x+40
-42-40=10x-6x
-82=4x
x=-20.5 done.
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Answer:

The area of the rectangle ABCD is \frac{2}{5} square units.

Step-by-step explanation:

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AB = \sqrt{\left(\frac{8}{3}-2 \right)^{2}+ (5-5)^{2}}

AB = \frac{2}{3}

BC = \sqrt{\left(\frac{8}{3}-\frac{8}{3}\right)^{2}+\left(\frac{28}{5}-5\right)^{2} }

BC = \frac{3}{5}

CD = \sqrt{\left(2-\frac{8}{3} \right)^{2}+\left(\frac{28}{5}-\frac{28}{5}  \right)^{2}}

CD = \frac{2}{3}

DA = \sqrt{\left(2-2\right)^{2}+\left(5-\frac{28}{5} \right)^{2}}

BC = \frac{3}{5}

Which satisfies all minimum characteristics for a rectangle. The area of the rectangle ABCD is the product of its base and its height, that is:

A = \left(\frac{2}{3}\right)\cdot \left(\frac{3}{5} \right)

A = \frac{2}{5}

The area of the rectangle ABCD is \frac{2}{5} square units.

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2 years ago
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For this case we have the following inequality: y < 3x + 1 < br/ >

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The shaded region represents the solution of the system of equations.

For the point (0, 0) we have:

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0 < 0 + 1 < br / >

0 < 1 < br / >

Therefore, the point (0, 0) is in the shaded region because it satisfies the inequality.

Then, the points that are on the line, are not part of the solution because the sign is of less strict.

Hope I helped ~~Laurel

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