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tino4ka555 [31]
3 years ago
13

Solve 6(x-7)=10(x+4) for x

Mathematics
2 answers:
Veseljchak [2.6K]3 years ago
8 0
6x - 42 = 10x + 40
6x - 82 = 10x
-82 = 4x
-82 / 4 = -20.5
x = -20.5

6(-20.5 - 7) = -165
10(-20.5 + 4) = -165


Ksenya-84 [330]3 years ago
3 0
6(x-7)=10(x+4)
6x-42=10x+40
-42-40=10x-6x
-82=4x
x=-20.5 done.
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sattari [20]

Answer:

(a): <u>x</u><u> </u><u>is</u><u> </u><u>3</u><u> </u><u>and</u><u> </u><u>ky</u><u> </u><u>is</u><u> </u><u>-</u><u>1</u>

<u>(</u><u>b</u><u>)</u><u>:</u><u> </u><u>k</u><u> </u><u>is</u><u> </u><u>-</u><u>2</u>

Step-by-step explanation:

Let: 3x + ky = 8 be <em>e</em><em>q</em><em>u</em><em>a</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>(</em><em>a</em><em>)</em>

x - 2 ky = 5 be <em>e</em><em>q</em><em>u</em><em>a</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>(</em><em>b</em><em>)</em>

<em> </em>Then multiply <em>e</em><em>q</em><em>u</em><em>a</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>(</em><em>a</em><em>)</em><em> </em>by 2:

→ 6x + 2ky = 16, let it be <em>e</em><em>q</em><em>u</em><em>a</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>(</em><em>c</em><em>)</em>

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<em>{ \sf{(6  + 1)x + (2 - 2)ky = (16  +  5)}} \\ { \sf{7x = 21}} \\ { \sf{x = 3}}</em>

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{ \sf{2ky = 3 - 5}} \\ { \sf{ky =  - 1}}

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