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8_murik_8 [283]
3 years ago
8

The standard formula for the volume of a rectangular pyramid is . If the pyramid is scaled proportionally by a factor of k, its

volume becomes V' = V × k3. Use your algebra skills to derive the steps that lead from to V' = V × k3 for a scaled rectangular pyramid. Show your work.
Mathematics
2 answers:
PolarNik [594]3 years ago
8 0

Answer:

The answer in the procedure

Step-by-step explanation:

we know that

The volume of a rectangular pyramid is equal to

V=\frac{1}{3}LWH

where

L is the length of the rectangular base

W is the width of the rectangular base

H is the height of the pyramid

If the pyramid is scaled proportionally by a factor of k

then

the new dimensions are

L=kL

W=kW

H=kH

substitute and find the new Volume V'

V'=\frac{1}{3}(kL)(kW)(kH)

V'=\frac{1}{3}(k^{3})LWH

V'=(k^{3})\frac{1}{3}LWH

V'=(k^{3})V

The new volume is equal to the scale factor k elevated to the cube multiplied by the original volume

Elenna [48]3 years ago
4 0

Answer:

V = πr2h

V' = π × (k × r)2 × (k × h)

   = π × k2 r2 × kh

   = k3 × πr2h

   = k3 × V

Step-by-step explanation:

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4 years ago
What is the value of x in both a &amp; b?
Stels [109]

Answer:

I've pretty much already solved this, in my discussion above:

| 3 | = 3

| –3 | = 3

So then x must be equal to 3 or equal to –3.

But how am I supposed to solve this if I don't already know the answer? I will use the positive / negative property of the absolute value to split the equation into two cases, and I will use the fact that the "minus" sign in the negative case indicates "the opposite sign", not "a negative number".

For example, if I have x = –6, then "–x " indicates "the opposite of x" or, in this case, –(–6) = +6, a positive number. The "minus" sign in "–x" just indicates that I am changing the sign on x. It does not indicate a negative number. This distinction is crucial!

Whatever the value of x might be, taking the absolute value of x makes it positive. Since x might originally have been positive and might originally have been negative, I must acknowledge this fact when I remove the absolute-value bars. I do this by splitting the equation into two cases. For this exercise, these cases are as follows:

a. If the value of x was non-negative (that is, if it was positive or zero) to start with, then I can bring that value out of the absolute-value bars without changing its sign, giving me the equation x = 3.

b. If the value of x was negative to start with, then I can bring that value out of the absolute-value bars by changing the sign on x, giving me the equation –x = 3, which solves as x = –3.

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8 0
3 years ago
Read 2 more answers
Please help as fast as you can.
weeeeeb [17]

Answer:

cos\theta=\sqrt{\frac{85}{121}}

tan\theta=\frac{6}{\sqrt{85}}

Step-by-step explanation:

given, sin\theta=\frac{6}{11}

since, sin^2\theta+cos^2\theta=1

cos^2\theta=1-sin^2theta

cos^2\theta[/tax]=1-[tex]\frac{36}{121}

                                 =\frac{121-36}{121}

                                 =\frac{85}{121}

cos\theta=\sqrt{\frac{85}{121}} answer

tan\theta=\frac{sin\theta}{cos\theta}

  tan\theta=\frac{6}{\sqrt{85}}  answer                      

7 0
3 years ago
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