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3 years ago

7

What is the slope of y = -1 + 3x?

1 answer:

zubka84 [21]3 years ago

8 0

Answer:

− 3

Step-by-step explanation:

We can rewrite the equation as: y = − 3 x + 0 This equation is now in the slope-intercept form. The slope-intercept form of a linear equation is: y = m x + b Where m is the slope and b is the y-intercept value. For: y = − 3 x + 0 the slope is: m = − 3

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One of the Same side angles of two parallel lines is 60° greater than the other. Find the two angles.

BARSIC [14]

Answer:

60,120

Step-by-step explanation:

We know that angles on the same side of the transversal always add up to 180 ( are supplementary)

Hence, taking one of the angles as x we get,

x+(60+x)=180

2x+60=180

2x=120

x=60

Hence, one angle is 60 degrees while the other 120 degrees

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3 years ago

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The sum of two numbers is ten. the difference between them is 8 . find the two numbers

alexira [117]

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y+8+y=10

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3 years ago

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IgorLugansk [536]

Answer:

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2 years ago

For what value of constant c is the function k(x) continuous at x = 0 if k =

nlexa [21]

The value of constant c for which the function k(x) is continuous is zero.

<h3>What is the limit of a function?</h3>

The limit of a function at a point k in its field is the value that the function approaches as its parameter approaches k.

To determine the value of constant c for which the function of k(x) is continuous, we take the limit of the parameter as follows:

$\mathbf{ \lim_{x \to 0^-} k(x) = \lim_{x \to 0^+} k(x) = 0 }$

$\mathbf{\implies \lim_{x \to 0 } \ \ \dfrac{sec \ x - 1}{x}= c }$

Provided that:

$\mathbf{\implies \lim_{x \to 0 } \ \ \dfrac{sec \ x - 1}{x}= \dfrac{0}{0} \ (form) }$

Using l'Hospital's rule:

$\mathbf{\implies \lim_{x \to 0} \ \ \dfrac{\dfrac{d}{dx}(sec \ x - 1)}{\dfrac{d}{dx}(x)}= \lim_{x \to 0} sec \ x \ tan \ x = 0}$

Therefore:

$\mathbf{\implies \lim_{x \to 0 } \ \ \dfrac{sec \ x - 1}{x}=0 }$

Hence; c = 0

Learn more about the limit of a function x here:

brainly.com/question/8131777

#SPJ1

5 0

2 years ago