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3 years ago

7

What is the slope of y = -1 + 3x?

1 answer:

zubka84 [21]3 years ago

8 0

Answer:

− 3

Step-by-step explanation:

We can rewrite the equation as: y = − 3 x + 0 This equation is now in the slope-intercept form. The slope-intercept form of a linear equation is: y = m x + b Where m is the slope and b is the y-intercept value. For: y = − 3 x + 0 the slope is: m = − 3

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riadik2000 [5.3K]

Answer:

$\frac{(\sin 18^\circ)}{75} = \frac{(\sin 35^\circ)}{x}$

Step-by-step explanation:

Incomplete question:

<em></em> $\angle CBD = 53^\circ$ <em></em>

<em></em> $\angle CAB = 35^\circ$ <em></em>

<em></em> $AB = 75$ <em></em>

<em></em>

<em>See attachment for complete question</em>

Required

Determine the equation to find x

First, is to complete the angles of the triangle (ABC and ACB)

$\angle ABC + \angle CBD = 180$ --- angle on a straight line

$\angle ABC + 53= 180$

Collect like terms

$\angle ABC =- 53+ 180$

$\angle ABC =127^\circ$

$\angle ABC + \angle ACB + \angle CAB = 180$ --- angles in a triangle

$\angle ACB + 127 + 35 = 180$

Collect like terms

$\angle ACB =- 127 - 35 + 180$

$\angle ACB =18$

Apply sine rule

$\frac{\sin A}{a} = \frac{\sin B}{b}$

In this case:

$\frac{\sin ACB}{AB} = \frac{\sin CAB}{x}$

This gives:

$\frac{(\sin 18^\circ)}{75} = \frac{(\sin 35^\circ)}{x}$

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