Answer:
Price of 1 adult ticket is <u>$10.8</u> and Price of 1 children ticket is <u>$5.4</u>.
Step-by-step explanation:
Given:
Number of adults = 2
Number of Children = 6
Total Amount of tickets sold = $54.
We need to find the price of one children's ticket and one adult ticket.
Solution:
Let the Cost of 1 adult ticket be 'x'.
Now Given:
Children tickets are on sale,half price of adult tickets.
Cost of 1 Children ticket = 
Total Amount is equal to Number of adults multiplied by Cost of adult ticket plus Number of Children multiplied by Cost of Children ticket.
Framing in equation for we get;
Cost of 1 adult ticket = $10.8
Cost of 1 children ticket = 
Hence Price of 1 adult ticket is <u>$10.8</u> and Price of 1 children ticket is <u>$5.4</u>.
Good morning,
Answer:
<h2>5+(-4) > -4 + (-7)</h2>
Step-by-step explanation:
5+(-4) = 5 - 4 = 1
-4 + (-7) = -(4+7) = -11
since 1 > -11 then 5+(-4) > -4 + (-7)
:)
Answer:
p=16
Step-by-step explanation:
Answer:
26
Step-by-step explanation:
[(7+3)5-4]/2+3
-To solve this equation you have to use PEMDAS
P- Parentheses
E- Exponents
M- Multiplication
D- Division
A- Addition
S- Subtraction-
- With MD and AS you work left to right of the equation since they are in the same spot. (PE[MD][AS])
Step 1) [(10)5-4]/2+3
- First you do "P," parentheses, so you add 7+3=10
Step 2) [50-4]/2+3
- Next you do "M," multiplication, and multiply 10x5=50
Step 3) [46]/2+3
- Then you do "S," subtraction, and subtract 50-4=46
(FYI: Steps 1-3 were still in the parentheses. We had to start with the parentheses in the parentheses, work PEMDAS, and now we are out of the parentheses and have to work PEMDAS on the rest of the problem.)
Step 4) 23+3
- Now we do "D," division, and divide 46/2=23
Step 5) 23+3=6
- Finally we do "A," addition, and add 23+3=26 so the answer is 26
(FYI: "/" means division)
