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mart [117]
3 years ago
9

Please help me with this

Mathematics
1 answer:
laiz [17]3 years ago
6 0

Answer:

u= 18 square millimeters

Step-by-step explanation:

The surface area formula is A=6a^2

You plug in the given surface area (1944) into A.

Divide both sides of the equation by 6. On the left you will get 324 and on the right you will eliminate 6 and get a^2.

The only way to get rid of an exponent is to square root it, and whatever you do to one side you have to do to the other. The square root of 324 is 18 and that is your answer.

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How do you solve 5 1/4 - 2 3/4
CaHeK987 [17]

5 \frac{1}{4 } - 2  \frac{3}{4}

\frac{21}{4}  -  \frac{11}{4}

\frac{21 - 11}{4}

\frac{10}{4}

\frac{5}{2}

7 0
3 years ago
Read 2 more answers
42:28
gogolik [260]

Answer:

The statements about arcs and angles that are true in the figure are;

1) ∠EFD ≅ ∠EGD

2) \overline{ED}\cong \overline{FD}

3) mFD = 120°

Step-by-step explanation:

1) ∠ECD + ∠CEG + ∠CDG + ∠GDE = 360° (Sum of interior angle of a quadrilateral)

∠CEG = ∠CDG = 90° (Given)

∠GDE = 60° (Given)

∴ ∠ECD = 360° - (∠CEG + ∠CDG + ∠GDE)

∠ECD = 360° - (90° + 90° + 60°) = 120°

∠ECD = 2 × ∠EFD (Angle subtended is twice the angle subtended at the circumference)

120° = 2 × ∠EFD

∠EFD = 120°/2 = 60°

∠EFD ≅ ∠EGD

∠ECD = 120°

∠EGD = 60°

∴∠EGD ≠ ∠ECD

2) Given that arc mEF ≅ arc mFD

Therefore, ΔECF and ΔDCF are isosceles triangles having two sides (radii EC and CF in ΔECF and radii EF and CD in ΔDCF

∠ECF = mEF = mFD = ∠DCF (Given)

∴ ΔECF ≅ ΔDCF (Side Angle Side, SAS, rule of congruency)

\\ \overline{EF}\cong \overline{FD} (Corresponding Parts of Congruent Triangles are Congruent, CPCTC)

∠FED ≅ ∠FDE (base angles of isosceles triangle)

∠FED + ∠FDE + ∠EFD = 180° (sum of interior angles of a triangle)

∠FED + ∠FDE = 180° - ∠EFD = 180° - 60° = 120°

∠FED + ∠FDE = 120° = ∠FED + ∠FED (substitution)

2 × ∠FED  = 120°

∠FED = 120°/2 = 60° = ∠FDE

∴ ∠FED = ∠FDE = ∠EFD =  60°

ΔEFD  is an equilateral triangle as all interior angles are equal

\\ \overline{EF}\cong \overline{FD}\cong \overline{ED} (definition of equilateral triangle)

\overline{ED}\cong \overline{FD}

3) Having that ∠EFD = 60° and ∠CFE = ∠CFD (CPCTC)

Where, ∠EFD = ∠CFE + ∠CFD (Angle addition)

60° = ∠CFE + ∠CFD = ∠CFE + ∠CFE (substitution)

60° = 2 × ∠CFE

∠CFE =60°/2 = 30° = ∠CFD

\overline{CF}\cong \overline{CD} (radii of the same circle)

ΔFCD is an isosceles triangle (definition)

∠CFD ≅ ∠CDF (base angles of isosceles ΔFCD)

∠CFD + ∠CDF + ∠DCF = 180°

∠DCF = 180° - (∠CFD + ∠CDF) = 180° - (30° + 30°) = 120°

mFD = ∠DCF (definition)

mFD = 120°.

5 0
3 years ago
Each person on a four-person relay team completed a race in approximately 18.1 seconds. How long did it take the relay team to f
likoan [24]

Answer:

72.4 seconds

Step-by-step explanation:

We are given that,

Time taken by each person in the team = 18.1 seconds

Number of members in the team = 4

It is required to find the total time taken by the team to finish the race.

Thus, the time taken taken = 4 × 18.1 = 72.4 seconds

Hence. the team finished the race in 72.4 seconds.

8 0
3 years ago
Jack has two square based pyramids that are the same size.he stick the square faces togather to make a new 3-d shape.how many fa
RideAnS [48]
I think it's
8faces and 6edges?
6 0
3 years ago
What’s the answer??
astra-53 [7]
Use parentheses for M and N
(5x {}^{2} + 7x - 4 )- ( - 3 {x}^{2} - 4x + 5)
一一一一一
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5 {x}^{2} + 7x - 4 + 3 {x}^{2} + 4x - 5
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3 years ago
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