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neonofarm [45]
3 years ago
15

Write a function in Java that implements the following logic: Given a string and an int n, return a string made of n repetitions

of the last n characters of the string. You may assume that n is between 0 and the length of the string, inclusive.
Computers and Technology
1 answer:
liubo4ka [24]3 years ago
8 0

Answer:

public class RepeatedString

{

public static void main(String[] args) {

 

 System.out.println(repeatString("apple", 3));

}

public static String repeatString(String str, int n) {

    String newString = str.substring(str.length()-n);

    System.out.println(newString);

    String ns = "";

    for(int i=0; i<n; i++) {

        ns += newString;

    }

    return ns;

}

}

Explanation:

- Create a function called repeatString that takes two parameter

- Get the last n characters of the string using substring function, and assign it to the newString variable

- Initialize an empty string to hold the repeated strings

- Initialize a for loop that iterates n times

- Inside the loop, add the repeated strings to the ns

- When the loop is done, return ns

- Inside the main, call the function

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Write a program that asks the user to enter a date in MM/DD/YYYY format that is typical for the US, the Philippines, Palau, Cana
stepladder [879]

Answer:

In Python:

txt = input("Date in MM/DD/YYYY format: ")

x = txt.split("/")

date=x[1]+"."

if(int(x[1])<10):

   if not(x[1][0]=="0"):

       date="0"+x[1]+"."

   else:

       date=x[1]+"."

   

if(int(x[0])<10):

   if not(x[0][0]=="0"):

       date+="0"+x[0]+"."+x[2]

   else:

       date+=x[0]+"."+x[2]

else:

   date+=x[0]+"."+x[2]

   

print(date)

Explanation:

From the question, we understand that the input is in MM/DD/YYYY format and the output is in DD/MM/YYYY format/

The program explanation is as follows:

This prompts the user for date in MM/DD/YYYY format

txt = input("Date in MM/DD/YYYY format: ")

This splits the texts into units (MM, DD and YYYY)

x = txt.split("/")

This calculates the DD of the output

date=x[1]+"."

This checks if the DD is less than 10 (i..e 1 or 01 to 9 or 09)

if(int(x[1])<10):

If true, this checks if the first digit of DD is not 0.

   if not(x[1][0]=="0"):

If true, the prefix 0 is added to DD

       date="0"+x[1]+"."

   else:

If otherwise, no 0 is added to DD

       date=x[1]+"."

   

This checks if the MM is less than 10 (i..e 1 or 01 to 9 or 09)

if(int(x[0])<10):

If true, this checks if the first digit of MM is not 0.

   if not(x[0][0]=="0"):

If true, the prefix 0 is added to MM and the full date is generated

       date+="0"+x[0]+"."+x[2]

   else:

If otherwise, no 0 is added to MM and the full date is generated

       date+=x[0]+"."+x[2]

else:

If MM is greater than 10, no operation is carried out before the date is generated

   date+=x[0]+"."+x[2]

This prints the new date

print(date)

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