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Mazyrski [523]
3 years ago
9

Use fuel with the _____________ rating recommended by your vehicle manufacturer. A ) Converter B) Emission C) Exhaust D) Octane

Computers and Technology
2 answers:
Free_Kalibri [48]3 years ago
7 0
I would say the correct answer is "octane". It is important that you use the fuel with  the correct octane rating recommended by the manufacturer. Among the choices it is only octane that is used as a rating for fuels. Hope this helps.
aleksklad [387]3 years ago
7 0

The answer is D: Octane

Octane rating is the fuel’s ability to resist “knocking” during combustion. Octane rating depends on what is recommended for your car’s engine by the manufacturer. For example, in the United States, the regular unleaded gasoline has typical octane ratings of between 87 (regular) to 90 (mid-grade). This is the cheapest and most standard option at the pump. The octane rating on gasoline pumps is prominently displayed on a yellow background in large black numbers. To help yourself determine your vehicle’s octane rating, always read the car’s manual to see the recommendations of the manufacturer.

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Match each method of communication with its intended purpose.
Scorpion4ik [409]

Answer:

1. a late breaking news story = to inform

2. a poetry reading = to entertain

3. an advertisement = to persuade

4. a small group assignment = to collaborate

Explanation:

1. A "breaking news" tells people of what is happening in the society. It <em>informs </em>them of the occurrence of an important event such as the plane crash of Kobe Bryant.

2. Poetry reading is meant to touch the attention of listeners. It tries to entertain them through the poem's interesting verses.

3. An advertisement is being shown/displayed in order to convince people to buy a particular product or service.

4. A group assignment allows the members of the group to contribute their ideas together. Such situation is known as "collaboration." They try to brainstorm together towards a common goal.

7 0
3 years ago
Write a new program called Lab7D that will read strings from a text file and turn them into "encrypted code". Create a bool func
Aliun [14]

Answer:

I am writing a C program for the first part and Python program for the second part of the question.    

<h2>1st program:</h2>

#include <stdio.h>  //to use input output functions

#include <stdlib.h>  // used here to access exit function

void main() {  //start of the main() function body

char fname[100], character;

// fname is the name of the input file which contains characters and character //variable is used to store characters

FILE *original, *temporary;  

/* two pointers of File type: original is used for the original input file and temporary is used for a temporary file name aux.txt */

printf("Enter the name of the text file to encrypt : ");

//prompts the user to enter the name of the file to be encrypted

scanf("%s",fname); //reads the name of the file from user

original=fopen(fname, "r"); //open the input file in read mode

if(original==NULL)  {

//displays the following message if the file is empty or does not exists

 printf("Cannot open original file");  

 exit(1);  }  //program exits

temporary=fopen("aux.txt", "w");

//creates a temporary file named aux.txt and open that file in write mode

if(temporary==NULL)  { //if temporary file could not be created

 printf("Cannot create a temporary file");

 fclose(original); //closes the original input file

 exit(2);  }  //program exits

while(1)  {

 character=fgetc(original);  

/*pointer original moves through the input file and gets input from original input file one character at a time and store it in character variable */

 if(character==EOF)  

//when all characters are obtained and pointer is at end of file  {

  break;  //the loop breaks }

 else   {  //if EOF is not yet reached

  character=character+100;  

//add 100 to each character to encrypt the characters

  fputc(character, temporary);

 // fputc() writes a single character at a time to aux file } }

fclose(original);  //closes input file

fclose(temporary); //closes aux file

original=fopen(fname, "w");  //opens input file in write mode

if(original==NULL) { //if file does not exist display following message

 printf("Cannot open the original file to write");

 exit(3);  } //program exits

temporary=fopen("aux.txt", "r"); //open aux.txt file in read mode

if(temporary==NULL)  { //if pointer temporary is NULL

 printf(" Cannot open temporary file to read");

 fclose(original);  //closes input file

 exit(4);  } //program exits

while(1)  {

 character=fgetc(temporary);

//obtains every character from aux file pointed by temporary

 if(character==EOF)  //if end of file is reaced {

  break;   } //the loop breaks

 else   { //if end of file is not reached

  fputc(character, original);  

//puts every character to input file }  }

printf(" %s is encrypted \n", fname);  

//displays this message when input file is successfully encrypted

//closes input and aux text files

fclose(original);

fclose(temporary); }  

Explanation:

The program first asks the user to enter the name of the file. Then the program uses two pointers original for input file and temporary for aux text file. It first opens the file whose name is entered by the user and reads that file by getting each single character using fgetc() until the pointer reaches the end of the file. While reading each character of the input file, it encrypts every character using and puts that encrypted content in temporary file names aux.txt using fputc() until the pointer reaches the end of the file. Lastly all the encrypted strings of the are placed in the original input text file.

<h2>Second program:</h2>

# bool function that accepts character as parameter and returns true if its a #vowel and false otherwise

def isVowel(character):  

   if character.lower() in 'aeiou':  #converts uppercase char to lowercase

       return True  #return true if character is a vowel    

   else:

       return False #returns false if input character is not a vowel

The program has a function isVowel() which takes a character as a parameter to check if that character is a vowel. If character is in uppercase  letters, it handles these characters using lower() method to convert the character to lowercase and then returns true if that character is a vowel otherwise returns false. To check the working of the function you can replace True and False with print statement such as:

if character.lower() in 'aeiou':

       print("It is a vowel")

   else:

       print("It is not a vowel")

And after that you can call this function and pass a character to it as:

isVowel('i')

5 0
3 years ago
The equation of certain traveling waves is y(x.t) = 0.0450 sin(25.12x - 37.68t-0.523) where x and y are in
NNADVOKAT [17]

Answer:

A. 0.0450

B. 4

C. 0.25

D. 37.68

E. 6Hz

F. -0.523

G. 1.5m/s

H. vy = ∂y/∂t = 0.045(-37.68) cos (25.12x - 37.68t - 0.523)

I. -1.67m/s.

Explanation:

Given the equation:

y(x,t) = 0.0450 sin(25.12x - 37.68t-0.523)

Standard wave equation:

y(x, t)=Asin(kx−ωt+ϕ)

a.) Amplitude = 0.0450

b.) Wave number = 1/ λ

λ=2π/k

From the equation k = 25.12

Wavelength(λ ) = 2π/25.12 = 0.25

Wave number (1/0.25) = 4

c.) Wavelength(λ ) = 2π/25.12 = 0.25

d.) Angular frequency(ω)

ωt = 37.68t

ω = 37.68

E.) Frequency (f)

ω = 2πf

f = ω/2π

f = 37.68/6.28

f = 6Hz

f.) Phase angle(ϕ) = -0.523

g.) Wave propagation speed :

ω/k=37.68/25.12=1.5m/s

h.) vy = ∂y/∂t = 0.045(-37.68) cos (25.12x - 37.68t - 0.523)

(i) vy(3.5m, 21s) = 0.045(-37.68) cos (25.12*3.5-37.68*21-0.523) = -1.67m/s.

5 0
3 years ago
What is the name of the nearest major galaxy to Milky-Way ?
nika2105 [10]
The Andromeda Galaxy would be my answer.
3 0
3 years ago
Design a TestScores class that has fields to hold three test scores. The class should have a constructor, accessor and mutator m
sweet-ann [11.9K]

Answer:

Answered below

Explanation:

class TestScores {

double test1;

double test2;

double test 3;

public TestScores (double test1, double test2, double teat3){

this.test1= test1;

this.test2 = test2;

this.test3 = teat3;}

//mutator

public setTest1(double test1){

this.test1 = test1;

}

//accessor

public double getTest1(){

return test 1;

}

//Write same accessors and mutators for test2 and test3

public double getTestAverage(){

double sum = test1+test2+test3;

return sum / 3;

}

}

class TestRun{

public static void main (String [] args){

TestScores scores = new TestScores(50.5, 40.0, 80.7)

int average = scores.getTestAverage();

System.out.print(average);

}

6 0
2 years ago
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