<u>Answer-</u>
<em>The coordinates of the orthocenter of △JKL is (-4, 8)</em>
<u>Solution-</u>
The orthocenter is the point where all three altitudes of the triangle intersect. An altitude is a line which passes through a vertex of the triangle and is perpendicular to the opposite side.
For a right angle triangle, the vertex at the right angle is the orthocentre of the triangle.
Here we are given the three vertices of the triangle are J(-4,-1), K(-4,8) and L(2,8)
If the triangle JKL satisfies Pythagoras Theorem, then triangle JKL will be a right angle triangle.
Applying distance formula we get,

As,




Therefore, the vertex at K (-4, 8) is the orthocentre.
Answer: Simplified Equation (10x-10)
Answer if 3=x is 20
Step-by-step explanation:
the original side lengths are 3x and (2x-5) so multiply both those by 2.
Now you have 6x and 4x-10.
Now combine those and you have 10x-10.
Then plug in 3 for x
Answer:
Most of the question is missing. If you could type out the rest, we might be able to help you.
Answer:
x-3
Step-by-step explanation:
x-3 x because we don't know the number of apples she has so you put a letter then -3 because 3 apples are given away
In this case, to prove what is required, we must use the Pythagorean theorem to find the diagonal of the square.
If the diagonal of the square is smaller than the diameter of the circle, then the square will fit perfectly in the circle without touching it.
Diagonal = Root ((7 ^ 2) + (7 ^ 2)) = 9.89 cm.
we observed that
9.89cm <11cm.
Therefore we show that:
the square will fit inside the circle without touching the edge of the circle