Answer:
12.
Step-by-step explanation:
(self-explanatory)
I hope this helps, have a nice day.

recall, for the scientific notation, it has to be using some power of 10, and the exponent of the base 10, is how many slots you're away from the <u>decimal point</u>. 0.007 uses 10⁻³ because 7.0 or 7. when we make it 0.007, we have to move the decimal point from in front of the 7 3 slots over to the left. Likewise, the 7000 is using 10³, because we moved the dot from 7. to 7000. , namely 3 slots to the right.
the missing value is there in the middle, notice is "7".
well, we can say that 7 is using 10⁰, however most of the time the 10⁰ is omitted and we settle for 7 alone, however scientific notation wise, that'd be it.
Answer:
approximately Normal with a mean of 3.2 million and a standard deviation of 0.32 million
Step-by-step explanation:
For normal distribution conditions
1) Sample size is greater than 30
2) Population standard deviation is known
3) population is normal distributed
Above any condition given problem if satisfied than it's distribution will approximately normal.
n = 40 > 30
Sample size(n) greater than 30 and population standard deviation is known.
So the distribution will approximately be normal
<em><u>Hope this helps!</u></em>
Answer: -4 yards
Step-by-step explanation:
The Warriors lost 11 yards in one play.
They then gained 7 yards in the next.
The total yards gained is therefore a sum of the yards lost and gained:
= -Yards lost + Yards gained
= - 11 + 7
= -4 yards
Using the t-distribution, we have that the 95% confidence interval for the true mean number of pushups that can be done is (9, 21).
For this problem, we have the <u>standard deviation for the sample</u>, thus, the t-distribution is used.
- The sample mean is of 15, thus
. - The sample standard deviation is of 9, thus
. - The sample size is of 10, thus
.
First, we find the number of degrees of freedom, which is the one less than the sample size, thus df = 9.
Then, looking at the t-table or using a calculator, we find the critical value for a 95% confidence interval, with 9 df, thus t = 2.2622.
The margin of error is of:

Then:

The confidence interval is:

Then


The confidence interval is (9, 21).
A similar problem is given at brainly.com/question/25157574