The square box is enough to fit the pizza with a diameter of 10 inches inside. Since the area of the square box is more than the area of the pizza, the pizza fits easily in the square box.
<h3>What is the area of the circle and the square?</h3>
The area of the circle is
Ac = πr² = πd²/4 sq. units
Where r is the radius and d is the diameter of the circle.
The area of the square is given by
As = s² sq. units
Where s is the length of the side of a square.
<h3>Calculation:</h3>
It is given that a pizza(in a circular shape) with a diameter d = 10 in is to be placed in a square box of the same length as the diameter of the pizza.
So,
The area of pizza is
Ap = Ac = πd²/4 sq. units
= π(10)²/4
= 25π
= 78.54 sq. in
Then, the area of the square box with the length same as the diameter of the pizza is,
As = d²
= 10²
= 100 sq. in
Since the area of the square is more than the area of the pizza (100 sq. inch > 78.54 sq. inch), the pizza easily fits into the square box.
Learn more about the area of a circle here:
brainly.com/question/15673093
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First, we inspect what type of sequence is the order of the coordinates:
a2 = 1
a3 = 2
a4 = 4
Getting the difference,
a3 - a2 = 1
a4 - a3 = 2
The differences are not equal; hence, the sequence is not arithmetic.
Getting the ratio:
a3/a2 = 2
a4/a3 = 2
The common ratio is 2. Using the general form for a geometric series:
an = a1 r^(n-1)
If n = 2
1 = a1 (2)^(2-1)
a1 = 1/2
So,
an = (1/2) (2)^(n-1)
The answer is the first option.
Answer:
y= -2x + 7
Step-by-step explanation:
The answer to this question is d
Use Pi, 3.14. Divide the Diameter by 3.14 and you should get your answer. That's all I know.
