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Karo-lina-s [1.5K]
3 years ago
10

7 freinds to a party if each freind will get 5 cookies and each box has 12 cookies how many boxes does shenika need to get

Mathematics
2 answers:
Ilya [14]3 years ago
7 0

Answer:

Shenika needs to get 3 boxes.

Step-by-step explanation:

7 friends x 5 cookies each = 35 cookies needed.

12 cookies in each box.

12 x 3 = 36 cookies.

dmitriy555 [2]3 years ago
3 0

Answer:

3 boxes

Step-by-step explanation:

To find the answer for the problem consider the amount of friends and how many cookies they will receive

First multiply 5 and 7 to find the amount of cookies she needs

5 x 7 = 35

She needs 35 cookies but there are 12 cookies per box

36 / 12 is 3

We are using 36 because it is the closest number to 35 that 12 can go into

She needs to get 3 boxes in order for each friend to get 5 cookies

Hope I helped :]

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Evaluate the infinite sum:
satela [25.4K]

Consider the <em>k</em>-th partial sum,

S_k = 1 + \dfrac2\pi + \dfrac3{\pi^2} + \cdots + \dfrac k{\pi^{k-1}}

More compactly,

\displaystyle S_k = \sum_{i=1}^k \frac i{\pi^{i-1}} = \frac{(1-\pi)k+\pi^{k+1}-\pi}{(1-\pi)^2\pi^{k-1}}

(this is just another case of a similar sum you asked about a while ago [24494877])

The infinite sum is the limit of the partial sum as <em>k</em> goes to infinity. We have

\displaystyle \lim_{k\to\infty} \frac{(1-\pi)k+\pi^{k+1}-\pi}{(1-\pi)^2\pi^{k-1}} = \frac\pi{(1-\pi)^2} \lim_{k\to\infty} \left(\frac{(1-\pi)k}{\pi^k} + \pi - \frac1{\pi^{k-1}} \right) = \boxed{\frac{\pi^2}{(1-\pi)^2}}

since the non-constant terms in the limit converge to 0.

Alternatively, recall that for |<em>x</em>| < 1, we have

\dfrac1{1-x} = \displaystyle \sum_{n=0}^\infty x^n

Differentiating both sides gives

\dfrac1{(1-x)^2} = \displaystyle \sum_{n=0}^\infty nx^{n-1} = \sum_{n=1}^\infty nx^{n-1}

also valid for |<em>x</em>| < 1. Take <em>x</em> = 1/<em>π</em> and you get the sum you want to compute.

5 0
2 years ago
PLEASE HELP Geometry
AveGali [126]
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answer
area inside square but outside circle = 13.7 in^2 (it's C.)
5 0
3 years ago
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