Answer:
(-1,-1)
Step-by-step explanation:
4-6 3-5
------- , ---------
2 2
(-2/2,-2/2)=(-1,-1)
The first three terms of sequence are 9 , 6 , 3
<em><u>Solution:</u></em>
Given the recursive function f(n) = f(n - 1) - 3
Where f(1) = 9
To find: First three terms of sequence
Substitute n = 2 , n = 3 and n = 4 in given recursive function
When n = 2
f(n) = f(n - 1) - 3
f(2) = f(2 - 1) - 3
f(2) = f(1) - 3
f(2) = 9 - 3 = 6
f(2) = 6
Thus second term is 6
When n = 3
f(3) = f( 3 - 1) - 3
f(3) = f(2) - 3
f(3) = 6 - 3 = 3
f(3) = 3
Thus the third term is 3
When n = 4
f(4) = f( 4 - 1) - 3
f(4) = f(3) - 3
f(4) = 3 - 3
f(4) = 0
Thus the fourth term is 0
Thus first three terms of sequence are 9 , 6 , 3
Answer:
There is no picture or graph to go with the question so I am afraid I will not be able to give you a specific answer.
To find out if a point (x, y) is on the graph of a line, we plug in the values into that equation and see if we get a true statement, such as 10 = 10. If we get something different, like 6 = 4, we know that the point is not on the line because it does not satisfy the equation. Plug in (-301, 601) into the equation of the line to see whether that point lies on it or not.
Step-by-step explanation:
Suppose the equation of the straight line that passes through E and F is this:
y = 7x + 2
We are to figure out whether or not the point (1, 10) lies on that line. In order to do this we would plug in (1, 10) into the equation, with 1 being x and 10 being y.
10 = 7(1) + 2 = 7 + 2 = 9
10 = 9 is a false statement. Therefore, the point (1, 10) does NOT lie on the line y = 7x + 2.
If you were to provide an image or graph that shows the equation of line AB then perhaps I would be able to answer your question with a specific answer.
