Given:
Seven times the smaller of two consecutive even integers is the same as -300 minus 4 times the larger integer.
To find:
The integers
.
Solution:
Let the smaller even integer be x.
So, larger even integer is x+2 because they are consecutive even integers.
Seven times the smaller integer = 7x
-300 minus 4 times the larger integer = -300-4(x+2)
Now,




Divide both sides by 11.


So, the smaller even integer is -28.

So, the larger even integer is -26.
The y intercept is the value of y when x=0. Substituting we get
y = 4
Answer: 4
2 more 10s then 11 is 31
1 more 10s then 11 is 21
3 more 10s then 11 is 41.
basic math :)
All real numbers greater than or equal to 1