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netineya [11]
3 years ago
10

The height of a rectangle is increasing at a rate of 111111 centimeters per hour and the width of the rectangle is decreasing at

a rate of 999 centimeters per hour. At a certain instant, the height is 333 centimeters and the width is 888 centimeters. What is the rate of change of the area of the rectangle at that instant (in square centimeters per hour)
Mathematics
1 answer:
Galina-37 [17]3 years ago
8 0

Answer:

Area of a rectangle = A = 295704 centimeters ^{2}

Step-by-step explanation:

Given Data:

At a certain instant,

height of a rectangle = h = 333 centimeters

width of a rectangle = w = 888 centimeters

To Find Out:

Area of a rectangle = A = ?

Formula:

Area of a rectangle = A = h × w

Solution:

Area of a rectangle = A = h × w

Area of a rectangle = A = 333 × 888

Area of a rectangle = A = 295704 centimeters ^{2}

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Step-by-step explanation:

Given:

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Taking the time derivative of V, we get

\dfrac{dV}{dt} = 4\pi r^2\dfrac{dr}{dt} = 4\pi\left(\dfrac{D}{2}\right)^2\dfrac{dr}{dt} = \pi D^2\dfrac{dr}{dt}

Solving for \frac{dr}{dt}, we get

\dfrac{dr}{dt} = \left(\dfrac{1}{\pi D^2}\right)\dfrac{dV}{dt} = \dfrac{1}{\pi(20\:\text{cm}^2)}(5\:\text{cm}^3\text{/min})

\:\:\:\:\:\:\:= 0.08\:\text{cm/min}

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Answer:

= − 7 /1 1  in fraction form

Step-by-step explanation:

STEP 1: Multiply by 1

1 + 1 0 + 2 5 = 1 8

+ 1 0 + 2 5 = 1 8                                                                                                                               STEP 2: Combine like terms

+ 1 0 + 2 5 = 1 8

1 1 + 2 5 = 1 8                                                                                                                       STEP 3: Subtract  2 5   from both sides of the equation

11x+25=18

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STEP 4: Simplify  by subtracting the numbers

1 1 + 2 5 − 2 5 = 1 8 − 2 5

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=  − 7 /1 1

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