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Bingel [31]
3 years ago
12

a print shop printed and assembled 8 books in 5 minutes. At this rate how many books can be printed and assembled 3 hours?

Mathematics
2 answers:
Alborosie3 years ago
7 0
5 min * 12 = 60 min = 1 hr * 3 = 3 hrs
8 * 12 = 96 * 3 = 288

288 Books can be assembled in 3 hrs
ozzi3 years ago
3 0
288 books.
8 books in 5 minutes.
60 minutes in one hour.
5 * 12 = 60
60 minutes * 3 = 3 hours
8 * 12 = 96
96 books in one hour.
96 * 3 = 288
288 books in three hours.
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I toss an unfair coin 12 times. This coin is 65% likely to show up heads. Calculate the probability of the following.
mars1129 [50]

Answer:

a. 0.0368

b. 0.99992131

c. 0.2039

d. 0.0048

e. 0.6533

Step-by-step explanation:

Let the probability of obtaining a head be p = 65% = 13/20 = 0.65. The probability of not obtaining a head is q = 1 - p = 1 -13/20 = 7/20 = 0.35

Since this is a binomial probability, we use a binomial probability.

a. The probability of obtaining 11 heads is ¹²C₁₁p¹¹q¹ = 12 × (0.65)¹¹(0.35) = 0.0368

b. Probability of 2 or more heads P(x ≥ 2) is

P(x ≥ 2) = 1 - P(x ≤ 1)

Now P(x ≤ 1) = P(0) + P(1)

= ¹²C₀p⁰q¹² + ¹²C₁p¹q¹¹

= (0.65)⁰(0.35)¹² + 12(0.65)¹(0.35)¹¹

= 0.000003379 + 0.00007531

= 0.0007869

P(x ≥ 2) = 1 - P(x ≤ 1)

= 1 - 0.00007869

= 0.99992131

c. The probability of obtaining 7 heads is ¹²C₇p⁷q⁵ = 792(0.65)⁷(0.35)⁵ = 0.2039

d. The probability of obtaining 7 heads is ¹²C₉q⁹p³ = 220(0.65)³(0.35)⁹ = 0.0048

e. Probability of 8 heads or less P(x ≤ 8) = ¹²C₀p⁰q¹² + ¹²C₁p¹q¹¹ + ¹²C₂p²q¹⁰ + ¹²C₃p³q⁹ + ¹²C₄p⁴q⁸ + ¹²C₅p⁵q⁷ + ¹²C₆p⁶q⁶ + ¹²C₇p⁷q⁵ + ¹²C₈p⁸q⁴

= = ¹²C₀(0.65)⁰(0.35)¹² + ¹²C₁(0.65)¹(0.35)¹¹ + ¹²C₂(0.65)²(0.35)¹⁰ + ¹²C₃(0.65)³(0.35)⁹ + ¹²C₄(0.65)⁴(0.35)⁸ + ¹²C₅(0.65)⁵(0.35)⁷ + ¹²C₆(0.65)⁶(0.35)⁶ + ¹²C₇(0.65)⁷(0.35)⁵ + ¹²C₈(0.65)⁸(0.35)⁴

= 0.000003379 + 0.00007531 + 0.0007692 + 0.004762 + 0.01990 + 0.05912 + 0.1281 + 0.2039 + 0.2367

= 0.6533

3 0
3 years ago
Algebra public opinion polls reported in newspapers are usually given with a margin of error. for example, a poll with a margin
sweet-ann [11.9K]

Answer:

Minimum percent of the vote that candidate Towne is expected to recieve:

m=51% - 6.3% * 51% =47.787%

Maximum percent of the vote that candidate Towne is expected to recieve:

M=51% + 6.3% * 51% = 54.213%

Solution:

Margin of error: E=6.3%

Minimum percent of the vote that candidate Towne is expected to recieve:

m=51% - E * 51%

m=51% - 6.3% * 51%

m=51% - 51% * 6.3 / 100

m=51% - 3.213%

m=47.787%

Maximum percent of the vote that candidate Towne is expected to recieve:

M=51% + E * 51%

M=51% + 6.3% * 51%

M=51% + 51% * 6.3 / 100

M=51% + 3.213%

M=54.213%


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3 years ago
Please help! Thanks!
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It's c u do distribute the -4 to everything in the ( )'s then combine the like terms
3 0
3 years ago
Read 2 more answers
Double a number increased by Ten equals twelve express the solution in 3 different ways
Zina [86]
First way: 1 doubled is 1+1, which is 2. 2 increased by 10 equals 12.

Second way: 1 doubled is 1*2, which equals 2. 2 increased by 10 equals 12.

7 0
3 years ago
Select the correct answer.
Slav-nsk [51]

Answer:b

x=3-y/7

Multiple 7

7x=3-y

Subtract 3

7x-3=-y

Times both sides by negative 1

-7x+3

3 0
3 years ago
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