All categories

2 years ago

Free response question please asap !

Mathematics

2 answers:

koban [17]2 years ago

7 0

Answer:

416 s correct

Step-by-step explanation:

Dmitrij [34]2 years ago

6 0

Step-by-step explanation:

416 s. udysuausissidhshs

You might be interested in

For a normal distribution with μ=500 and σ=100, what is the minimum score necessary to be in the top 60% of the distribution?

STatiana [176]

Answer:

475.

Step-by-step explanation:

We have been given that for a normal distribution with μ=500 and σ=100. We are asked to find the minimum score that is necessary to be in the top 60% of the distribution.

We will use z-score formula and normal distribution table to solve our given problem.

$z=\frac{x-\mu}{\sigma}$

Top 60% means greater than 40%.

Let us find z-score corresponding to normal score to 40% or 0.40.

Using normal distribution table, we got a z-score of $-0.25$ .

Upon substituting our given values in z-score formula, we will get:

$-0.25=\frac{x-500}{100}$

$-0.25*100=\frac{x-500}{100}*100$

$-25=x-500$

$-25+500=x-500+500$

$x=475$

Therefore, the minimum score necessary to be in the top 60% of the distribution is 475.

3 0

2 years ago

A researcher selects two samples of equal size and computes a mean difference of 1.0 between the two sample means. If the pooled

s344n2d4d5 [400]

Answer:

The Cohen's D is given by this formula:

$D = \frac{\bar X_A -\bar X_B}{s_p}$

Where $s_p$ represent the deviation pooled and we know from the problem that:

$s^2_p = 4$ represent the pooled variance

So then the pooled deviation would be:

$s_p = \sqrt{4}= 2$

And the difference of the two samples is $\bar X_a -\bar X_b = 1$ , and replacing we got:

$D = \frac{1}{2}= 0.5$

And since the value for D obtained is 0.5 we can consider this as a medium effect.

Step-by-step explanation:

Previous concepts

Cohen’s D is a an statistical measure in order to analyze effect size for a given condition compared to other. For example can be used if we can check if one method A has a better effect than another method B in a specific situation.

Solution to the problem

The Cohen's D is given by this formula:

$D = \frac{\bar X_A -\bar X_B}{s_p}$

Where $s_p$ represent the deviation pooled and we know from the problem that:

$s^2_p = 4$ represent the pooled variance

So then the pooled deviation would be:

$s_p = \sqrt{4}= 2$

And the difference of the two samples is $\bar X_a -\bar X_b = 1$ , and replacing we got:

$D = \frac{1}{2}= 0.5$

And since the value for D obtained is 0.5 we can consider this as a medium effect.

7 0

3 years ago

Evaluate 24. 5 PLS AND THANK YOU!!!

GREYUIT [131]

Answer:

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Step-by-step explanation:

Step 1: Define

2⁴ · 5

Step 2: Evaluate

Exponents: 16 · 5
Multiplication: 80

4 0

2 years ago

Solve the initial value problem. 7y′−4y=e−πt2, y(0)=a Let a0 be the value of a for which the transition from one type of long-ru

densk [106]

Answer:

as shown in the attached file

Step-by-step explanation:

The detailed steps and application of differential equation, the use of integrating factor to generate the solution and to solve for the initial value problem is as shown in the attached file.

8 0

2 years ago

A typical high school student consumes 67.5 pounds of sugar per year. As part of a new nutrition plan, each member of the track

tino4ka555 [31]

Answer:

54 Pounds

Step-by-step explanation:

We know that they start off with 67.5 pounds of sugar and they need to reduce it by 20%. We also know from the problem that we want to know the MAXIMUM amount of sugar consumed by each track member.

The typical high school student consumes about 67.5 pounds of sugar per year. That is our first piece of the problem

67.5

We now know that 20% of it needs to be reduced. This means that we can multiply it by 0.8 because that is 20% less than 100% of the sugar.

67.5 x 0.8

This leads the answer to be 54 Pounds

Hope this helped :D

4 0

3 years ago