Solution:
Given:
A circle with the sector details;
![\begin{gathered} r=19\text{ }in \\ \theta=135^0 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20r%3D19%5Ctext%7B%20%7Din%20%5C%5C%20%5Ctheta%3D135%5E0%20%5Cend%7Bgathered%7D)
The area of a sector is given by;
![\begin{gathered} A=\frac{\theta}{360}\times\pi r^2 \\ A=\frac{135}{360}\times\pi\times19^2 \\ A=\frac{1083\pi}{8}\text{ }in^2 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20A%3D%5Cfrac%7B%5Ctheta%7D%7B360%7D%5Ctimes%5Cpi%20r%5E2%20%5C%5C%20A%3D%5Cfrac%7B135%7D%7B360%7D%5Ctimes%5Cpi%5Ctimes19%5E2%20%5C%5C%20A%3D%5Cfrac%7B1083%5Cpi%7D%7B8%7D%5Ctext%7B%20%7Din%5E2%20%5Cend%7Bgathered%7D)
Therefore, the area of the sector is;
I don’t see the whole thing so I can’t even answer it sorry
Answer:
x<-6
Step-by-step explanation:
-3x>18
Divide by -3, flip the sign since dividing by a negative.
x<-6
Answer:
36
Step-by-step explanation:
Calculation to Find two positive numbers
First step
Let the first positive number be a
Let the second positive number be b
Second step is to create the Equation
a^2+b= 54....... Equation (1)
b = 54-a^2........ Equation (2)
Third step is to find the product
Product= a(54-a)^2 = 54a-a^3
Fourth step is to differentiate
dP/dx = 54-3a^2
dP/dx = 0
Fifth step is to solve for 54-3a^2 = 0
Hence,
3a^2=54
a^2 = 18
Last step
a= √(18)
b= 54-(√(18))^2
b=54-18
b = 36
Therefore the two positive numbers are 36
Answer:
20%
Step-by-step explanation: