See the present value of annuity ordinary through Google
PVAO=750×(((1−(1+0.05÷12)^(−12
×30))÷(0.05÷12)))=139,711
Answer:
Answers are below
Step-by-step explanation:
The maximum is π/6. The minimum is 5π/6.
I graphed the equation below, so you can see where I got my answers.
Answer:
1. 27
2.6
Step-by-step explanation:
1.
remember the priorities of operations :
1. brackets
2. exponents
3. multiplications and divisions
4. (and truly last) additions and subtractions
so,
16 + 14÷2 + 3×5 - 11 =
16 + 7 + 15 - 11 = 23 + 4 = 27
2.
5 coins are tossed at the same time.
each coin has a result (head or tail).
but the observed event is the sum of all tails that show when tossing the 5 coins.
so, the possible outcomes are
0 tails
1 ...
2 ...
3 ...
4 ...
5 tails
so, in total, 6 different possible outcomes.
Answer:
B
Step-by-step explanation:
We are given that the position of a particle is modeled by the function:
And we want to find the times for which the <em>speed</em> of our particle is <em>increasing. </em>
In other words, we want to find the times for which our <em>acceleration</em> is positive (a(t)>0).
So first, we will find our acceleration function. We can differentiate twice.
By taking the derivative of both sides with respect to <em>t</em>, we acquire:
Differentiate:
This is our velocity function. We can differentiate once more to acquire the acceleration function. Therefore:
Differentiate:
If our speed is increasing, our acceleration must be positive. So:
By substitution:
Now, we can solve for <em>t:</em>
<em /><em />
<em />
Therefore, the only interval for which the speed of the particle is increasing (i.e. the acceleration is positive) is for all times t>4.
So, our answer is B.