What is the solution to 2log9(x)=log^9(8)+log9(x-2)
2 answers:
2log9(x)=log^9(8)+log9(x-2)
Log₉x² = log₉8 + log₉(x-2)
Log₉x² = log₉(8×(x-2))
Log₉x² = log₉8x-16
Log₉x² - log₉8x-16 = 0
Log₉(x²/(8x-16)) = 0
x²/(8x-16) = 9°
x² = 1 × 8x-16
x²-8x+16 = 0
x²-4x-4x+16 = 0
x(x-4)-4(x-4) = 0
(x-4)(x-4) =0
Therefore x = 4.....
Answer:
X= 4
Step-by-step explanation:
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