Answer:
The probability that a container will be shipped even though it contains 2 defectives if the sample size is 88, will be 
Step-by-step explanation:
The first step is to count the number of total possible random sets of taking a sample size of 88 engines over 1212 engines of the population, so ![\left[\begin{array}{ccc}1212\\88\end{array}\right] =1212C88=4.7205x10^{135}](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1212%5C%5C88%5Cend%7Barray%7D%5Cright%5D%20%3D1212C88%3D4.7205x10%5E%7B135%7D)
The second step is to count the number of total possible random sets of taking a sample size of 88 engines over 1210 engines (discounting the 2 defective engines) as the possible ways to succeed, so ![\left[\begin{array}{ccc}1210\\88\end{array}\right] =1212C88=4.0596x10^{135}](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1210%5C%5C88%5Cend%7Barray%7D%5Cright%5D%20%3D1212C88%3D4.0596x10%5E%7B135%7D)
Finally we need to compute
, therefore the probability that a container will be shipped is
Subsitution
4x+y=210
minus 4x both sides
y=210-4x
sub 210-4x for y in other equation
3x+2(210-4x)=195
3x+420-8x=195
-5x+420=195
minus 420 both sides
-5x=-225
divide both sides by -5
x=45
sub back
y=210-4x
y=210-4(45)
y=210-180
y=30
x=45
y=30
(x,y)
(45,30)
B is incorrect which means it is the answer
Answer:
i believe it would be d square root of 17