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3 years ago

How does cancer affect the cell cycle? What is done differently in the cell cycle?

1 answer:

5 0

Cancer cells affect the cell cycle by not following the checkpoints and dividing abnormally and not getting destroyed by the process of apoptosis leading to the formation of tumours.

In the cell cycle during the mitotic phase the cell divides resulting in two daughter cells and segregation of DNA occurs in this. In cell cycle, there are checkpoints of signalling pathways which determine when the cell has to grow and divide. The healthy cells follow the cell cycle.

Explanation:

Cancer cells become immortal and result in faulty proteins which are not required by the system. The cancer cells grow uncontrollably and are abnormally shaped.

The cell cycle has check points at S phase and G2 phase before it enters the Mitotic phase of division. Normal cells follow the checkpoints.

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Where are ribosomes produced?

lord [1]

Answer:

In bacterial cells, ribosomes are synthesized in the cytoplasm through the transcription of multiple ribosome gene operons. In eukaryotes, the process takes place both in the cell cytoplasm and in the nucleolus, which is a region within the cell nucleus.

Hope this helps!

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2 years ago

When the body responds to its own cells as foreign antigens this results in?

Artemon [7]

its autoimmune disease

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3 years ago

The health belief model of __________ was developed to understand why so few people participated in health screening programs su

Ber [7]

<span>Irwin Rosenstock developed this model. His research was used to show why so few people undertake preventative measures for diseases and illnesses. This model shows that people tend to think that they are healthier than they might be, so there is no need for them to get screenings or other types of treatment.</span>

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3 years ago

The human body maintains a temperature of around 98.6 degrees at all times. Enzymes are involved in almost every chemical reacti

Butoxors [25]

Answer:

The enzyme function best at a specific temperature.

Explanation:

Enzyme activity is affected by temperature. Each enzyme has a specific temperature range in which it works most effectively. Most biological enzymes present in the human body have an ideal temperature range of around 98.6 degrees.

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3 years ago

7) Calculate ∆G^0' for the following reaction: glucose + 6O2 → 6 CO2 + 6 H2O. Is this reaction exergonic or endergonic?

san4es73 [151]

The reaction is endergonic.

<h2>Procedure - Determination of the Gibbs reaction type</h2>

<h3>Thermochemical model</h3>

First, we need to determine the Gibbs free energy function ( $\Delta G_{o}$ ), in kilojoules, of the entire reaction by this formula:

$\Delta G_{o} = \Sigma\limits_{j=1}^{m} n_{j}\cdot g_{o, j} - \Sigma\limits_{i=1}^{p}n_{i}\cdot g_{o,i}$ (1)

Where:

$n_{i}$ - Number of kilomoles of the i-th reactive, in kilomoles.
$n_{j}$ - Number of kilomoles of the j-th product, in kilomoles.
$g_{o,i}$ - Specific Gibbs free energy function of the i-th reactive, in kilojoules per kilomole.
$g_{o,j}$ - Specific Gibbs free energy function of the j-th reactive, in kilojoules per kilomole.

<h3>Data from thermochemical tables</h3>

From thermochemical tables we have the following information:

Reactives

$g_{glu} = -2871596\,\frac{kJ}{kmol}$ , $g_{O_{2}} = 0\,\frac{kJ}{kmol}$

$n_{glu} = 1\,kmol$ , $n_{O_{2}} = 6\,kmol$

Products

$g_{CO_{2}} = -137150\,\frac{kJ}{kmol}$ , $g_{H_{2}O} = -237180\,\frac{kJ}{kmol}$

$n_{CO_{2}} = 6\,kmol$ , $n_{H_{2}O} = 6\,kmol$

<h3>Determination of the Gibbs free energy function</h3>

Now we proceed to determine the Gibbs free energy function and later determine the nature of the <em>thermochemical</em> reaction:

$\Delta G_{o} = (6\,kmol)\cdot \left(-137150\,\frac{kJ}{kmol} \right) + (6\,kmol)\cdot \left(-237180\,\frac{kJ}{kmol} \right)-(1\,kmol)\cdot \left(-2871596\,\frac{kJ}{kmol} \right) - (6\,kmol)\cdot \left(0\,\frac{kJ}{kmol} \right)$

$\Delta G_{o} = 625616\,kJ$

The Gibbs free energy function of the <em>entire</em> reaction is 625616 kilojoules.

<h3>Analysis of the result</h3>

The Gibbs free energy function has a <em>positive</em> sign, which means that this reaction is endergonic.

To learn more on Gibbs free energy, we kindly invite to check this verified question: brainly.com/question/9552459

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2 years ago