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mylen [45]
3 years ago
10

Which number is the same as 12 thousand and 14 tens

Mathematics
1 answer:
seraphim [82]3 years ago
7 0

Answer:

12,014

Step-by-step explanation:

you are adding 12,000 and 14

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Anon25 [30]

Step-by-step explanation:

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4 0
3 years ago
12x−5y=−20 y=x+4 x=x=x, equals y=y=y, equals
aksik [14]

Answer:

The solution is (0, 4)

Step-by-step explanation:

Please pay attention to the first two equations and drop the last two:

12x−5y=−20 y=x+4 x=x=x, equals y=y=y   should ideally be:

12x−5y=−20

y=x+4

Let's find x.  Substitute x + 4 for y in the first equation, obtaining:

12x - 5(x + 4) = -20

Carrying out the indicated multiplication, we get:

12x - 5x - 20 = -20, or 7x = 0

If x = 0 then y must be 0 + 4, or 4.  

The solution is (0, 4)

8 0
3 years ago
The volume of a fish tank is 60 cubic feet. If the density is 0.3 fish over feet cubed, how many fish are in the tank? 200 9 100
FinnZ [79.3K]

Answer:

There are 18 fish in the fish tank.

Step-by-step explanation:

The volume of a fish tank is 60 cubic feet: V = 60 ft³.

The density is 0.3 fish over feet cubed. d = 0.3 fish/ft³

We can find the number of fish using proportions. The required conversion factor is 0.3 fish/ft³. The number of fish is:

60 ft³ × (0.3 fish/ft³) = 18 fish

There are 18 fish in the fish tank.

5 0
3 years ago
Match the solution given below on the number line to its inequality.
dimaraw [331]
A is the best one’s
8 0
3 years ago
If the work required to stretch a spring 2 ft beyond its natural length is 9 ft-lb, how much work is needed to stretch it 18 in.
Blababa [14]

If the work required to stretch a spring 2 ft beyond its natural length is 9 ft-lb,then the work that is needed to stretch it 18 inches beyond its natural length is 81 ft.lb.

Given that work required to stretch a spring 2 ft beyond its natural length is 9 ft-lb.

We are required to find the work that is needed to stretch 18 inches beyond its natural length.

Multiplication is basically finding out the product of two or more numbers.

Work required to stretch the spring 2 feet beyond its natural length=9 ft. lb.

So, to find the work that is required to stretch the spring 18 feet beyond its natural length, we have to multiply 9 with 9 which will give us 81. So the work required is 81 ft.lb.

Hence if the work required to stretch a spring 2 ft beyond its natural length is 9 ft-lb,then the work that is needed to stretch it 18 inches beyond its natural length is 81 ft.-lb.

Learn more about multiplication at brainly.com/question/10873737

#SPJ4

5 0
1 year ago
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