If i just completed my daily Mindkeeper five-kilometer training run, how many meters did I run

Mathematics

1 answer:

galina1969 [7]3 years ago

5 0

Answer:

5000

Step-by-step explanation:

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What is the answer to this question about dividing fractions5 5⁄6 ÷ 3 2⁄4=

Lady_Fox [76]

[~Answer~] (4.):
<em>Hello there! I'm Avery, and I'm here to help you! I mostly believe the answer </em><em>is 1 2/3

+++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++</em>

[~Answer Explanation~]:

First:

Convert any mixed numbers to fractions.

Reduce fractions where possible.

Then your initial equation becomes:

356÷72

Applying the fractions formula for division,

=35×26×7

=70/42

Simplifying 70/42, the answer is

=1 2/3

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[~Last Messages~]:

Okay, I really hope my answer is correct.

I am truly sorry if it's wrong :(

Have a great morning, afternoon, or night. <333

[-!AveryIsSomeHowAlive!-]

3 0

1 year ago

Please help me <br> 20 points

svetlana [45]

Answer is C............

3 0

3 years ago

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marishachu [46]

Answer:

I think the answer would be B.

4 0

3 years ago

lim x rightarrow 0 1 - cos ( x2 ) / 1 - cosx The limit has to be evaluated without using l'Hospital'sRule.

zaharov [31]

Answer with Step-by-step explanation:

Given

$f(x)=\frac{1-cos(2x)}{1-cos(x)}\\\\\lim_{x \rightarrow 0}f(x)=\lim_{x\rightarrow 0}(\frac{1-(cos^2{x}-sin^2{x})}{1-cos(x)})\\\\(\because cos(2x)=cos^2x-sin^2x)\\\\\lim_{x \rightarrow 0}f(x)=\lim_{x\rightarrow 0}(\frac{1-cos^2x}{1-cos(x)}+\frac{sin^2x}{1-cosx})\\\\=\lim_{x\rightarrow 0}(\frac{(1-cosx)(1+cosx)}{1-cosx}+\frac{sin^2x}{1-cosx})\\\\=\lim_{x\rightarrow 0}((1+cosx)+\frac{sin^2x}{1-cosx})\\\\\therefore \lim_{x \rightarrow 0}f(x)=1$