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Stella [2.4K]
3 years ago
9

If i just completed my daily Mindkeeper five-kilometer training run, how many meters did I run

Mathematics
1 answer:
galina1969 [7]3 years ago
5 0

Answer:

5000

Step-by-step explanation:

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Please help me please​
Vesnalui [34]
X=7. 42/14=3. so x+5 times 3 = 7x-13. do the math, x =7. 7+5=12. 7(7)-13= 36. 12x3=36. boom.
4 0
3 years ago
Read 2 more answers
A bag contains red, green, and yellow marbles. The probability of selecting a red marble is 35%. What is the probability of not
KonstantinChe [14]

Probablity of selecting a red marble= 35%

Probablity of not selecting a red marble= 100%-35%

=65%

Hope it helps you. Please mark brainliest.

6 0
3 years ago
Write the following number by entering one digit in each box of the place value chart.
shutvik [7]

Answer:

The number itself is 508.231

Step-by-step explanation:

Any multiplying each of the numbers, we will have the specific places

Hundreds

5 * 100 = 500

Tenths

0 * 10 = 0

ones

8 * 1 = 8

Tenths = 2 * 1/10 = 2/10 = 1/5 = 0.2

Hundredths = 3/100 = 0.03

Thousandths = 1/1000 = 0.001

So we simply sum all these to get the number itself as follows

500 + 8 + 0.2 + 0.03 + 0.001 = 508.231

5 0
3 years ago
The route used by a certain motorist in commuting to work contains two intersections with traffic signals. The probability that
tekilochka [14]

Answer:

a) P(X∩Y) = 0.2

b) P_1 = 0.16

c) P = 0.47

Step-by-step explanation:

Let's call X the event that the motorist must stop at the first signal and Y the event that the motorist must stop at the second signal.

So, P(X) = 0.36, P(Y) = 0.51 and P(X∪Y) = 0.67

Then, the probability P(X∩Y) that the motorist must stop at both signal can be calculated as:

P(X∩Y) = P(X) + P(Y) - P(X∪Y)

P(X∩Y) = 0.36 + 0.51 - 0.67

P(X∩Y) = 0.2

On the other hand, the probability P_1 that he must stop at the first signal but not at the second one can be calculated as:

P_1 = P(X) - P(X∩Y)

P_1 = 0.36 - 0.2 = 0.16

At the same way, the probability P_2 that he must stop at the second signal but not at the first one can be calculated as:

P_2 = P(Y) - P(X∩Y)

P_2 = 0.51 - 0.2 = 0.31

So, the probability that he must stop at exactly one signal is:

P = P_1+P_2\\P=0.16+0.31\\P=0.47

7 0
3 years ago
What is 74 divided by 9??
Rama09 [41]
Its 8.22.. the 2 repeats
3 0
3 years ago
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