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Ronch [10]
3 years ago
9

AYOOO THIS IS A TEST. someone please help me.

Mathematics
1 answer:
anyanavicka [17]3 years ago
5 0

Answer:

Step-by-step explanation:

でもうん、彼女はすっごくきれいだ

でもうん、彼女はすっごくきれいだ

でもうん、彼女はすっごくきれいだ

でもうん、彼女はすっごくきれいだ

でもうん、彼女はすっごくきれいだ

でもうん、彼女はすっごくきれいだ

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Enter the equation of the line in slope-intercept form.
antiseptic1488 [7]

Answer:

ajfbgaulfgsuidglml

Step-by-step example:

4 0
2 years ago
What are the zeroes of f(x) = x2 + 5x + 6?
Vera_Pavlovna [14]

Answer:

Zeros are x = −2, −3 .

Step-by-step explanation:

Given : f(x) = x² + 5x + 6.

To find : What are the zeroes of f(x).

Solution : We have given that

f(x) = x² + 5x + 6.

To find the zeros of the function we need to set f(x) = 0.

x² + 5x + 6 = 0.

On factoring

x² + 3x +2x + 6 = 0.

Taking common x from first two term and 2 from last two terms

x ( x + 3) +2 ( x +3) = 0.

On grouping

(x + 3) (x + 2)  = 0

Now, x + 3 = 0   and x + 2 = 0

x = -3 and x = -2

Therefore, Zeros are x = −2, −3 .

3 0
3 years ago
5.1million x 2.9 thousand
d1i1m1o1n [39]

Answer:

fourteen billion seven hundred ninety millio

4 0
3 years ago
Simplify the expression
kow [346]

Answer:

<h3>           f(x) = 5x² + 2x</h3><h3>           g(x) = 6x - 6</h3>

Step-by-step explanation:

\dfrac{5x^3-8x^2-4x}{6x^2-18x+12}\\\\6(x^2-3x+2)\ne0\ \iff\ x=\frac{3\pm\sqrt{9-8}}{2}\ne0\ \iff\ x\ne2\ \wedge\ x\ne1\\\\\\\dfrac{5x^3-8x^2-4x}{6x^2-18x+12}=\dfrac{x(5x^2-8x-4)}{6(x^2-3x+2)}=\dfrac{x(5x^2-10x+2x-4)}{6(x^2-2x-x+2)}=\\\\\\=\dfrac{x[5x(x-2)+2(x-2)]}{6[x(x-2)-(x-2)]} =\dfrac{x(x-2)(5x+2)}{6(x-2)(x-1)}=\dfrac{x(5x+2)}{6(x-1)}=\dfrac{5x^2+2x}{6x-6}\\\\\\f(x)=5x^2+2x\\\\g(x)=6x-6

4 0
2 years ago
Type SSS, SAS, ASA, SAA, or HL to<br> describe these triangles.
Bingel [31]

Answer:

SAS

Step-by-step explanation:

There is one common side (S)

both the triangles have 90° common (A)

Opposite sides are equal which is given (S)

They both are right angled triangles

5 0
2 years ago
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