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zysi [14]
3 years ago
15

Does anyone know the answer?

Mathematics
1 answer:
Vika [28.1K]3 years ago
3 0

Answer:

<FBC=<DBG

Step-by-step explanation:

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A die is a cube with 1 edgemeasuring 0.62 inches. Find the total volume of the 5 dice in agame.
igomit [66]

The volume of one die is the edge to the power of 3:

V=0.62^3in^{3^{}}.

The total volume is five times the above volume:

5V=1.19164in^3.

Answer:

1.19164in^3

5 0
1 year ago
Help!!!!!!!!!!!!!!!!!!!!!!!!!!!
shepuryov [24]

Answer:

4

Step-by-step explanation:

5 0
3 years ago
A scale drawing of a lake has a scale of 1 cm to 80 m. If the actual width of the lake is 1,000 m, what is the width of the lake
Andreas93 [3]

Answer: 12.5 cm

Step-by-step explanation:

Equation would be:

1:80

?:1000

So you'll just have the cross multiply the equation above to find ? ( scale drawing lake). It'll be 1000*1/80 which will be 12.5 cm.

                               

7 0
3 years ago
Which expression is equivalent to (x superscript four-thirds baseline x superscript two-thirds Baseline ) superscript one-third
Andrei [34K]
<h3><u>The equivalent expression is:</u></h3>

(x^{\frac{4}{3}}x^{\frac{2}{3}})^{\frac{1}{3}} = x^{\frac{2}{3}

<em><u>Solution:</u></em>

<em><u>Given expression is:</u></em>

\displaystyle (x^{\frac{4}{3}}x^{\frac{2}{3}})^{\frac{1}{3}}

We have to find the equivalent expression

We can simplify the above expression using law of exponents

<em><u>Use the following law of exponents:</u></em>

a^m \times a^n = a^{m+n}

Therefore,

\displaystyle (x^{\frac{4}{3}}x^{\frac{2}{3}})^{\frac{1}{3}} = (x^{\frac{4}{3}+\frac{2}{3}})^{\frac{1}{3}}\\\\Simplify\\\\\displaystyle (x^{\frac{4}{3}}x^{\frac{2}{3}})^{\frac{1}{3}} = (x^2)^\frac{1}{3}

<em><u>Use another law of exponent</u></em>

(a^m)^n = a^{mn}

Therefore,

(x^{\frac{4}{3}}x^{\frac{2}{3}})^{\frac{1}{3}} = x^{\frac{2}{3}

Thus the equivalent expression is found

5 0
3 years ago
Read 2 more answers
Please help me understand how to do this and the answer!
Murrr4er [49]
Turn F(x) into vertex form:

y=x^2+8x+6
y-6=x^2+8x
y-6+16=x^2+8x+16
y+10=(x+4)^2
Thus the vertex is (-4,-10)

This is a minimum because the parabola is up up, or is positive
6 0
3 years ago
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