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3 years ago

Can someone help with my homework?

Mathematics

1 answer:

USPshnik [31]3 years ago

5 0

Step-by-step explanation:

To divide by a fraction, multiply by its reciprocal.

1) (m² / 9) / (n² / m)

(m² / 9) × (m / n²)

m³ / (9n²)

2) (4 / y) / (2 / (yx))

(4 / y) × (yx / 2)

3) (x² / y) / (1 / y)

(x² / y) × (y / 1)

x²

4) (3 / b) / (9 / a²)

(3 / b) × (a² / 9)

a² / (3b)

5) (x² / 16) / (16 / y²)

(x² / 16) × (y² / 16)

x²y² / 256

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2x + y = -4 2x + 3y = 4

kirill115 [55]

Answer: x=4 ; y= -4

Step-by-step explanation:

2x + y = -4 .(-3)

2x + 3y = 4

-6x-3y=12

2x + 3y = 4

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x= 16

x=4

2x + 3y = 4

2.4+3y=4

8+3y=4

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A softball team is ordering pizza to eat after their tournament. They plan to order cheese pizzas that cost $6 each and four-top

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Answer:

Step-by-step explanation:

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Step-by-step explanation:

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Arthur hs 20/8 cups of dish wahing detergent, he uses 1/4 cup for each load, how many loads can he do

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2 years ago

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icang [17]

Answer:

$x=-2\\x=2$

(You only need to give one solution)

Step-by-step explanation:

We have the following equation

$(x^2+1)^2-5x^2-5=0$

First, we need to foil out the parenthesis

$x^4+2x^2+1-5x^2-5=0$

Now we can combine the like terms

$x^4-3x^2-4=0$

Now, we need to factor this equation.

To factor this, we need to find a set of numbers that add together to get -3 and multiply to give us -4.

The pair of numbers that would do this would be 1 and -4.

This means that our factored form would be

$(x^2-4)(x^2+1)=0$

As the first binomial is a difference of squares, it can be factored futher into

$(x^2+1)(x+2)(x-2)=0$

Now, we can get our solutions.

The first binomial will produce two complex (Not real) solutions.

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$x-2=0\\\\x=2$

So our solutions to this equation are

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3 years ago