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Mathematics

1 answer:

Lynna [10]3 years ago

6 0

You have a function $y= \dfrac{3}{2} \left(1+\sin \left(\dfrac{2t+1}{2}\cdot \pi\right) \right)$ .
Since the range of the function $y=\sin x$ is $[-1,1]$ you have that

$-1\le \sin \left(\dfrac{2t+1}{2}\cdot \pi\right)\le 1 \\ 0\le 1+\sin \left(\dfrac{2t+1}{2}\cdot \pi\right) \le 2 \\ 0\le \dfrac{3}{2} \left(1+\sin \left(\dfrac{2t+1}{2}\cdot \pi\right) \right)\le 3$ .
Answer: The range of given function is [0,3] and the correct choice is C.

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3 years ago

Show all work to identify the asymptotes and state the end behavior of the function f(x)=3x/x-9

lorasvet [3.4K]

Using the asymptote concept, we have that:

The vertical asymptote is x = 9.

The horizontal asymptote is y = 3.

The end behavior is that as $x \rightarrow \infty, y \rightarrow 3$ .

<h3>What are the asymptotes of a function f(x)?</h3>

The vertical asymptotes are the values of x which are outside the domain, which in a fraction are the zeroes of the denominator.

The horizontal asymptote is the value of f(x) as x goes to infinity, as long as this value is different of infinity.

In this problem, the function is:

$f(x) = \frac{3x}{x - 9}$

For the vertical asymptote, we have that:

x - 9 = 0 -> x = 9.

For the horizontal asymptote:

$y = \lim_{x \rightarrow \infty} f(x) = \lim_{x \rightarrow \infty} \frac{3x}{x - 9} = \lim_{x \rightarrow \infty} \frac{3x}{x} = \lim_{x \rightarrow \infty} 3 = 3$

Hence, the end behavior is that as $x \rightarrow \infty, y \rightarrow 3$ .

More can be learned about asymptotes at brainly.com/question/16948935

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2 years ago

Find x from this triangle

algol [13]

Hello,

we are going to use the theorem of the bissectrice. (if this word is good in english)

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